Question

给定一个如下文件：

(u'castro', 5.4716387933635691)
(u'catcher', 5.4716387933635691)
(u'center', 4.3730265046954591)
(u'caus', 5.0661736852554045)

如何将此文件读取到python字典，然后根据分数对其进行排序？

d={}
with open("scores.txt") as f:
    for line in f:
        key, val= line.strip().split()
        d[key]=val

我试图在这种情况下按val排序，然后以下面的形式得到结果：

(u'castro', 5.4716387933635691)
(u'catcher', 5.4716387933635691)
(u'caus', 5.0661736852554045)
(u'center', 4.3730265046954591)

Answer 1

这会产生一个嵌套列表：

from operator import itemgetter

with open("scores.txt") as f:
    lst = [i.rstrip("\n")[1:-1].split(", ") for i in f.readlines()]


for i in lst:
    i[1] = float(i[1])
    i[0] = i[0][2:-1]

lst.sort(key=itemgetter(1), reverse=True)

输出：

>>> lst
[['castro', 5.471638793363569], ['catcher', 5.471638793363569], ['caus', 5.0661736852554045], ['center', 4.373026504695459]]

将名称写入文件：

with open("scores2.txt", "w") as f:
    for i in lst:
        f.write("{}\n".format(i[0]))

Answer 2

d = sorted(d.items(), key=lambda x: x[1], reverse=True)

Answer 3

Python词典没有顺序，您只能创建一个排序表示。

import operator
d={}
with open("scores.txt") as f:
  for line in f:
     key, val= line.strip().split()
     d[key]=val

sorted_d = sorted(d.items(), key=operator.itemgetter(0))
print sorted_d

将文件读入字典并尝试排名

3 个答案: