Question

如何从两个表中获取first_name，email，user_type？

table 1 ( recruiter_master )
      1)recruiter_id
      2)first_name
      3)email
      4)password
      5)user_type

    table 2 ( freelancer_master )
       1)freelancer_id
       2)first_name
       3)email
       4)password
       5)user_type

我想获取recruiter_id / freelancer_id，first_name和email，user_type。如果电子邮件和密码匹配相关表的返回数据。

SELECT * 
FROM `recruiter_master`,   `freelancer_master`
WHERE  (recruiter_master.email="abc@gmail.com" AND 
        recruiter_master.password="abc123") OR 
       (freelancer_master.email="abc@gmail.com" AND 
        freelancer_master.password="abc123")

它返回两个表数据。

Answer 1

您需要的是Func<Person, Person>

Union

Answer 2

SELECT
recruiter_id,
freelancer_id,
recruiter_master.first_name,
recruiter_master.email,
recruiter_master.user_type
FROM recruiter_master
INNER JOIN freelancer_master 
ON recruiter_master.email = freelancer_master.email
AND recruiter_master.password = freelancer_master.password
WHERE  (recruiter_master.email="abc@gmail.com" AND recruiter_master.password="abc123")

你想要：

recruiter_master.first_name,
recruiter_master.email,
recruiter_master.user_type

或：

freelancer_master.first_name,
freelancer_master.email,
freelancer_master.user_type

此致

如何从两个表中获取first_name，email，user_type？

2 个答案: