Question

在我的数组中是这样的，

var myColumnDefs = [

    {a: "hh", b: "hh", c: "jk", d: "ggh", e: "hvh"},

    {a: "dd", b: "gg", d: "nn", e: "rr", f: "jj"},.....
]

我想过滤数据并在新数组中插入数据

var newarray = {a,b,c,d,e,f}

＆安培;另一个数组

var mysecondarray = [

                {hh,hhjk,ggh,hvh},

                {dd,gg,nm,rr,jj},....
]

Answer 1

您可以使用 map() 和 indexOf() 并执行此类操作

＆＃13;

var myColumnDefs = [
  {
    a: "hh",
    b: "hh",
    c: "jk",
    d: "ggh",
    e: "hvh"
  },

  {
    a: "dd",
    b: "gg",
    d: "nn",
    e: "rr",
    f: "jj"
  }
];

var arr1 = [],
  arr2 = [];

// iterate over `myColumnDefs` array and generate value array
arr2 = myColumnDefs.map(function(v, i) {
  // get keys from object
  var keys = Object.keys(v);
  // iterate over key values and generate the value array and then return
  return keys.map(function(k) {
    // check key value is in `arr1`, push if not
    if (arr1.indexOf(k) == -1)
      arr1.push(k);
    // return corresponding value based on key
    return v[k];
  });
});

document.write('First Array : <pre>' + JSON.stringify(arr1, null, 3) + '</pre> Second Array : <pre>' + JSON.stringify(arr2, null, 3) + '</pre>');

＆＃13;

Answer 2

假设您希望结果在数组中，那么这应该有效。结果是在一个对象中进行进一步处理。

＆＃13;

var myColumnDefs = [{ a: "hh", b: "hh", c: "jk", d: "ggh", e: "hvh" }, { a: "dd", b: "gg", d: "nn", e: "rr", f: "jj" }],
    result = function (array) {
        var r = { keys: [], data: [] };
        array.forEach(function (a) {
            r.data.push(Object.keys(a).map(function (k) {
                !~r.keys.indexOf(k) && r.keys.push(k);
                return a[k];
            }));
        });
        return r;
    }(myColumnDefs);

document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');

＆＃13;

Answer 3

假设mysecondarray的数组数组的顺序相同。

试

var columns = {}; //newarray 
var values = []; //mysecondarray 
myColumnDefs.forEach(function(value){

   var arr = [];
   for (var key in value)
   {
      columns[key] = true;
      arr.push(value[key]);
   }
   values.push(arr);

})
console.log("columns are " + JSON.stringify(Object(columns).keys, 0, 4));
console.log("values are " + JSON.stringify(values, 0, 4));

如何在数组循环中过滤数据

3 个答案: