使用smsManager
课程,我可以同时向多个号码发送相同的短信吗?或者我需要做一些循环?
我想从我的应用程序中发送短信而不是通过短信程序。
答案 0 :(得分:7)
这里我附上源代码,我已经做了以编程方式发送消息。
SMS:
public class SMS extends Activity {
Button btnSendSMS;
EditText txtPhoneNo;
EditText txtMessage;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
btnSendSMS = (Button) findViewById(R.id.btnSendSMS);
txtPhoneNo = (EditText) findViewById(R.id.txtPhoneNo);
txtMessage = (EditText) findViewById(R.id.txtMessage);
btnSendSMS.setOnClickListener(new View.OnClickListener()
{
public void onClick(View v)
{
String message = txtMessage.getText().toString();
String phoneNo = txtPhoneNo.getText().toString();
StringTokenizer st=new StringTokenizer(phoneNo,",");
while (st.hasMoreElements())
{
String tempMobileNumber = (String)st.nextElement();
if(tempMobileNumber.length()>0 && message.trim().length()>0) {
sendSMS(tempMobileNumber, message);
}
else {
Toast.makeText(getBaseContext(),
"Please enter both phone number and message.",
Toast.LENGTH_SHORT).show();
}
}
// if (phoneNo.length()>0 && message.length()>0)
// sendSMS(phoneNo, message);
// else
// Toast.makeText(getBaseContext(),
// "Please enter both phone number and message.",
// Toast.LENGTH_SHORT).show();
}
});
}
private void sendSMS(String phoneNumber, String message)
{
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,
new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
new Intent(DELIVERED), 0);
//---when the SMS has been sent---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS sent",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(getBaseContext(), "Generic failure",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(getBaseContext(), "Null PDU",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(getBaseContext(), "Radio off",
Toast.LENGTH_SHORT).show();
break;
}
}
},new IntentFilter(SENT));
//---when the SMS has been delivered---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered",
Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
}
}
SmsReceiver:
public class SmsReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
//---get the SMS message passed in---
Bundle bundle = intent.getExtras();
SmsMessage[] msgs = null;
String str = "";
if (bundle != null)
{
//---retrieve the SMS message received---
Object[] pdus = (Object[]) bundle.get("pdus");
msgs = new SmsMessage[pdus.length];
for (int i=0; i<msgs.length; i++)
{
msgs[i] = SmsMessage.createFromPdu((byte[])pdus[i]);
str += "SMS from " + msgs[i].getOriginatingAddress();
str += " :";
str += msgs[i].getMessageBody().toString();
str += "\n";
}
//---display the new SMS message---
Toast.makeText(context, str, Toast.LENGTH_SHORT).show();
}
}
}
并需要在manifest中设置权限 READ_SMS,RECIEVE_SMS。 这是您向单个用户发送消息的方式..
这是你可以向多个用户发送消息的方式。 ........................................... 假设您需要向多个用户发送消息,您可以用逗号分隔编号 例如。 5558,5554。
这是你可以用逗号分隔两个数字的方法 上面代码中使用的字符串标记符类
您可以在调用SendSms功能的地方应用此逻辑,并每次都传递适当的电话号码
它对我来说很好..我可以尝试一下.. 这是你的问题的答案吗?
谢谢,
勒凯什