我在listview中的两个复选框中使用第一个colunm复选框工作第二列checkbox1在列表视图中无法一次只选择一个
点击here查看截图
i tried this code please help me
我试过这段代码请帮帮我
public class ListViewAdapter extends ArrayAdapter<Friend> {
private List<Friend> myFriends;
private Activity activity;
private int selectedPosition = -1;
public ListViewAdapter(Activity context, int resource, List<Friend> objects) {
super(context, resource, objects);
this.activity = context;
this.myFriends = objects;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder;
LayoutInflater inflater = (LayoutInflater) activity.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);
// If holder not exist then locate all view from UI file.
if (convertView == null) {
// inflate UI from XML file
convertView = inflater.inflate(R.layout.item_listview, parent, false);
// get all UI view
holder = new ViewHolder(convertView);
// set tag for holder
convertView.setTag(holder);
} else {
// if holder created, get tag from view
holder = (ViewHolder) convertView.getTag();
}
holder.checkBox.setTag(position);
holder.checkBox1.setTag(position+1);
holder.friendName.setText(getItem(position).getName());
if (position == selectedPosition) {
holder.checkBox.setChecked(true);
} else holder.checkBox.setChecked(false);
if(holder.checkBox.getTag().equals(position){
holder.checkBox.setOnClickListener(onStateChangedListener(holder.checkBox, position));
}else{
holder.checkBox1.setOnClickListener(onStateChangedListener(holder.checkBox1, position));
}
return convertView;
}
private View.OnClickListener onStateChangedListener(final CheckBox checkBox, final int position) {
return new View.OnClickListener() {
@Override
public void onClick(View v) {
if (checkBox.isChecked()) {
selectedPosition = position;
} else {
selectedPosition = -1;
}
notifyDataSetChanged();
}
};
}
private static class ViewHolder {
private TextView friendName;
private CheckBox checkBox,checkBox1;
public ViewHolder(View v) {
checkBox = (CheckBox) v.findViewById(R.id.check);
checkBox1 = (CheckBox) v.findViewById(R.id.check1);
friendName = (TextView) v.findViewById(R.id.name);
}
}
每次第一列复选框工作正常时,也无法调用此onStateChangedListener方法,否则部分不工作控件不会到这里holder.checkBox1.getTag()holder.checkBox1.setOnClickListener(onStateChangedListener(holder.checkBox1,位置));
In the hole list view only one checkbox should select how will achive this any one please help me
答案 0 :(得分:0)
使复选框的标记成为一个字符串,其中包含列表中的位置和框的ID
我经常使用function showForm($atts = array()) {
$keywords = filter_input(INPUT_GET, 'sas-keywords');
$form = '<form action="' . get_permalink($atts['results-page']) . '"name="sas-form" class="sas-form form-inline pull-xs-right"><input type="hidden" name="sas-search" value="1"><input type="text" class="form-control" name="sas-keywords" value="' . htmlentities($keywords) . '"/>' . ' <input type="submit" value="Search" class="btn btn-secondary" /></form>';
return $form;
}
示例:
string.split()
然后,在获取标签时:
holder.checkbox.setTag(checkboxid + ";" + position);
,其中