Question

我正在使用automapper将视图模型和实体模型相互映射，一切都很好，但现在我有一个不同的场景，AutoMapper无法映射我的类型。

我的视图模型：

   public class CriminalSearchViewModel
   {

    public CriminalSearchParamsViewModel SearchParameters { get; set; }

    public SelectList GenderSelectList { get; set; }

    public SelectList NationalitySelectList { get; set; }

    public SelectList CrimeSelectList { get; set; }

    public SelectList CriminalStatusSelectList { get; set; }
}

第二视图模型：

public class CriminalSearchParamsViewModel
{
    [Required]
    public string FirstName { get; set; }

    public string LastName { get; set; }

    public int? GenderID { get; set; }

    public int? StatusID { get; set; }

    public string CNIC { get; set; }

    public int? AgeFrom { get; set; }

    public int? AgeTo { get; set; }

    public double? Height { get; set; }

    public int Weight { get; set; }

    public int? NationalityID { get; set; }
}

和我的商业模式：

public class CriminalSearch
{

    public string FirstName { get; set; }

    public string LastName { get; set; }

    public int? GenderID { get; set; }

    public int? StatusID { get; set; }

    public string CNIC { get; set; }

    public int? AgeFrom { get; set; }

    public int? AgeTo { get; set; }

    public double? Height { get; set; }

    public int Weight { get; set; }

    public int? NationalityID { get; set; }

}

我已经定义了映射：

Mapper.CreateMap<CriminalSearch, CriminalSearchParamsViewModel>();

也尝试了这个：

 Mapper.CreateMap<CriminalSearchParamsViewModel,CriminalSearchViewModel>()
  .ForMember(dest => dest.SearchParameters, opt =>
     opt.MapFrom(src => Mapper.Map<CriminalSearchParamsViewModel, CriminalSearch>(src)));

在控制器中我想尝试：

public ActionResult Search(CriminalSearchViewModel searchVM)
{
    if (ModelState.IsValid)
    {
        var searchParams = searchVM.SearchParameters;
        var criminalSearch = AutoMapper.Mapper.Map<CriminalSearch>(searchParams);
        _criminalService.SearchCriminals(criminalSearch);
    }
        return View();
}

但它总是抛出异常：

缺少类型映射配置或不支持的映射。

映射类型：     CriminalSearchParamsViewModel - ＆gt; CriminalSearch     NationalCriminals.UI.ViewModels.CriminalSearchParamsViewModel - ＆gt; NationalCriminals.Core.Models.CriminalSearch

目的地路径：     CriminalSearch

来源价值：     NationalCriminals.UI.ViewModels.CriminalSearchParamsViewModel

任何人都可以告诉我出了什么问题？

Answer 1

您只需要更改方法CreateMap中的通用参数的顺序：

Mapper.CreateMap<CriminalSearchParamsViewModel,CriminalSearch>()

这是因为第一个通用arg是源类型，第二个是目的地，它不是两种方式，如果你想要，你必须声明两者从一种类型映射到另一种类型，反之亦然：

Mapper.CreateMap<CriminalSearchParamsViewModel,CriminalSearch>()
Mapper.CreateMap<CriminalSearch,CriminalSearchParamsViewModel>()

方法CreateMap的描述如下：

AutoMapper.Mapper.CreateMap<SourceClass, DestinationClass>();

建议：Using AutoMapper: Creating Mappings

一种类型的属性映射到另一种类型的实例

1 个答案: