此网站为我节省了数百万次,但现在我正在尝试制作类似于this网站标题部分的内容,并且无法让它发挥作用。我希望有人帮我解决以下问题:
这是我的示例代码:
<div class="container">
<div class="row" style="padding-top: 50px;">
<div class="col-md-4">
<div id="first" class="cube color1"></div>
<div id="second" class="cube color3" style="display: none;"></div>
</div>
<div class="col-md-4">
<div id="first" class="cube color2"></div>
<div id="second" class="cube color1" style="display: none;"></div>
</div>
<div class="col-md-4">
<div id="first" class="cube color3"></div>
<div id="second" class="cube color2" style="display: none;"></div>
</div>
</div>
<div class="row" style="padding-top: 50px;">
<div class="col-md-4">
<div id="first" class="cube color3"></div>
<div id="second" class="cube color2" style="display: none;"></div>
</div>
<div class="col-md-4">
<div id="first" class="cube color2"></div>
<div id="second" class="cube color1" style="display: none;"></div>
</div>
<div class="col-md-4">
<div id="first" class="cube color1"></div>
<div id="second" class="cube color3" style="display: none;"></div>
</div>
</div>
</div>
javascript:
<script>
setInterval(hide, 2000);
function switchDivs()
{
var first = document.getElementById("first");
var second = document.getElementById("second");
}
function hide() {
document.getElementById("first").style.display="none";
document.getElementById("second").style.display="block";
}
function show() {
document.getElementById("first").style.display="block";
document.getElementById("second").style.display="none";
}
</script>
链接到jsfiddle
我不明白为什么它不会将所有“第一”div改为“second”,它只改变第一个div。比下一个问题是如何使该动作随时间重复,优选地更像是6个位置/框中的每一个的随机计时器。
很快:我需要将id =“first”的div与id =“second”的div交换,加载页面后延迟5-10秒。在相同的延迟之后,我需要它们切换回只显示id =“first”的div等等...(类似于setInterval函数)。
答案 0 :(得分:0)
答案 1 :(得分:0)
setInterval(function() { $(".color-blocks .col-md-4").each(function() { $(this).children().toggle(); }); }, 2000);
一段简单的代码可能会有所帮助,而且更简单。
工作小提琴:https://jsfiddle.net/65k788u6/3/
当您使用ids
时,这些应该是唯一的,因此请使用toggle()
以使其看起来更简单。
答案 2 :(得分:0)
.getElementById
来获取与给定CSS查询选择器匹配的所有元素(或.querySelectorAll
,而不是.querySelector
,而只选择一个项目(并且仅按其ID属性)获得单个元素。)setTimeout
代替setInterval
作为一般最佳做法。
var rows = document.querySelectorAll(".col-md-4");
var indices = getIndices(rows);
setTimeout(flipRows, 5000);
function getIndices() {
var arr = [];
for (var i = 0, len = rows.length; i < len; i++) {
arr.push(i);
}
return arr;
}
function flipRows() {
if (indices.length == 0) {
indices = getIndices();
}
var index = Math.random() * indices.length >>> 0;
var randomRow = rows[indices[index]];
indices.splice(index, 1);
flipRow(randomRow);
setTimeout(flipRows, 5000); // run again in 5 seconds
}
function flipRow(row) {
var first = row.querySelector(".first");
var second = row.querySelector(".second");
if (first.style.display === "none") {
first.style.display = "block";
second.style.display = "none";
} else {
first.style.display = "none";
second.style.display = "block";
}
}
.color1 { background-color: pink;}
.color2 { background-color: lightblue;}
.color3 { background-color: lightgreen;}
<div class="container">
<div class="row" style="padding-top: 50px;">
<div class="col-md-4">
<div class="first cube color1">first</div>
<div class="second cube color3" style="display: none;">second</div>
</div>
<div class="col-md-4">
<div class="first cube color2">first</div>
<div class="second cube color1" style="display: none;">second</div>
</div>
<div class="col-md-4">
<div class="first cube color3">first</div>
<div class="second cube color2" style="display: none;">second</div>
</div>
</div>
<div class="row" style="padding-top: 50px;">
<div class="col-md-4">
<div class="first cube color3">first</div>
<div class="second cube color2" style="display: none;">second</div>
</div>
<div class="col-md-4">
<div class="first cube color2">first</div>
<div class="second cube color1" style="display: none;">second</div>
</div>
<div class="col-md-4">
<div class="first cube color1">first</div>
<div class="second cube color3" style="display: none;">second</div>
</div>
</div>
</div>