Question

我想在用户每次连接到互联网时检查特定更新。我尝试了以下代码：

unfortunately app is getting stopped while checking for network

Broadcast receiver for checking internet connection in android app

的Manifest.xml

<uses-permission android:name="android.permission.INTERNET"/>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>
<receiver android:name=".UpdateReceiver" >
    <intent-filter>
        <action android:name="android.net.conn.CONNECTIVITY_CHANGE" />
    </intent-filter>
</receiver>

爪哇

public class UpdateReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {
        ConnectivityManager connectivityManager = (ConnectivityManager) 
        context.getSystemService(Context.CONNECTIVITY_SERVICE );
        NetworkInfo activeNetInfo = connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
        boolean isConnected = activeNetInfo != null && activeNetInfo.isConnectedOrConnecting();   
        if (isConnected)       
            Log.i("NET", "connecte" +isConnected);   
        else Log.i("NET", "not connecte" +isConnected);
    }
}

我的问题是这些代码只接收一次，如果用户断开wifi并重新连接BroadcastReceiver无法通知。感谢任何帮助。

Answer 1

在我的应用中实施支票后，查看是否有任何互联网连接。你可以看看这个 -

[SqlExceptionHelper] - ERROR: column "league_id" does not exist

您可以在OnCreate方法中初始化此类的对象。

最后在上传文件之前调用此类的方法。

public class ConnectionDetector {

private Context context;

public ConnectionDetector(Context cont){
this.context = cont;
}

public boolean isConnectingToInternet(){
ConnectivityManager connectivity = (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);
if (connectivity != null)
{
   NetworkInfo[] info = connectivity.getAllNetworkInfo();
   if (info != null) {
   for (int i = 0; i < info.length; i++) {
   if (info[i].getState() == NetworkInfo.State.CONNECTED) {
        return true;
    }
}
}

}
return false;
}
}

EDITED ::

Boolean isInternetConnected = cd.isConnectingToInternet();
if (isInternetConnected)
{
    //perform your job here.
}

希望这有帮助。

如何在android中检测用户何时连接到wifi或移动互联网

1 个答案: