Question

例如，我有一个像

这样的字符串

"look[+3],panel button layout[+3],feature[+2]it 's very sleek looking with a very good front panel button layout , and it has a great feature set . "

“look [+3]”表示该句话涉及某个项目的某个方面，而[+3]表示它是一个评分为3的正面评论。（这实际上来自亚马逊评论数据集。）

我想把它拆分为

X: "it 's very sleek looking with a very good front panel button layout , and it has a great feature set ."

Y: [("look", 3), ("panel button layout", 3), ("feature", 2)]

Answer 1

一种选择是在字符串或逗号开头之后捕获所有内容，直到[并在[+之后提取数字：

>>> import re
>>> s = "look[+3],panel button layout[+3],feature[+2]it 's very sleek looking with a very good front panel button layout , and it has a great feature set . "
>>> re.findall(r"(?:^|,)(.*?)\[\+?(\-?\d+)\]", s)
[('look', '3'), ('panel button layout', '3'), ('feature', '2')]
>>>
>>> s = "darn diopter adjustment dial[-1]"
>>> re.findall(r"(?:^|,)(.*?)\[\+?(\-?\d+)\]", s)                                                            
[('darn diopter adjustment dial', '-1')]

其中：

(?:^|,)是一个非捕获组，可以匹配字符串的开头或逗号
(.*?)是任意次数的非贪婪匹配
\[\+?(\-?\d+)\]会匹配一个开头[，后跟一个可选的+，后跟一个捕获组，该捕获组将捕获一个或多个数字（开头有一个可选的- ），然后是结束]

Answer 2

您可以使用re.findall('(.*\[\+\d+\],?)', s)获取所需的Y输出。

Answer 3

try this regular expression：

([^\]]+[[^\]])+(.*)

你的key / val对是1美元，摘要是2美元。

编辑：虽然re不支持每组多个匹配（只有最后一次捕获可用），the new regex module does：

>>> m = regex.search(r"([^\]]+[[^\]])+(.*)", "look[+3],panel button layout[+3],feature[+2]it 's very sleek looking with a very good front panel button layout , and it has a great feature set . ")
>>> m.group(1)
',feature[+2]'
>>> m.captures(1)
['look[+3]', ',panel button layout[+3]', ',feature[+2]']
>>> m.group(2)
"it's very sleek looking with a very good front panel button layout , and it has a great feature set . "

如何编写正则表达式以在Python中查找多个字符串

3 个答案: