Question

我正在努力找出使用单表全文加入普通多表查询的语法。我无法理解语法

这是现有的语法，可以正常工作：

SELECT * FROM products,categories,sub_categories 
WHERE products.approved = 1 
AND products.main_category = categories.id 
AND products.sub_category = sub_categories.id

我添加全文的努力并未削减它。这是我试图用于搜索的查询：

MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) 
AGAINST ('keyword') AS score FROM products 
WHERE MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) AGAINST('keyword')

这就是我想出来的，但是对于我不知道的（可能是显而易见的）原因，它不起作用。

SELECT * FROM products,categories,sub_categories 
WHERE products.approved = 1 
AND products.main_category = categories.id 
AND products.sub_category = sub_categories.id
AND MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) 
AGAINST ('keyword') AS score FROM products 
WHERE MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) AGAINST('keyword')

非常感谢任何帮助！

Answer 1

最低限度，你需要将“得分”移动到SELECT子句中，并将两个WHERE clases与AND组合。

SELECT *, 
  MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) 
  AGAINST ('keyword') AS score
FROM products,categories,sub_categories 
WHERE products.approved = 1 
  AND products.main_category = categories.id 
  AND products.sub_category = sub_categories.id
  AND MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) AGAINST('keyword')

我还强烈建议使用ANSI连接语法重写整个查询，以使其更具可读性：

SELECT *, 
  MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) 
  AGAINST ('keyword') AS score
FROM products
  INNER JOIN categories on products.main_category = categories.id
  INNER JOIN sub_categories on products.sub_category = sub_categories.id
WHERE products.approved = 1 
  AND MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,details) AGAINST('keyword')

Answer 2

感谢大家。即时通讯与其他语言相当不错，但是带有mysql语法的flakey。老实说，当我看到你的代码时，事情就开始出现了！我可以看看你是如何得出这个结果的。我给它一个旋转，但看起来不错。

Answer 3

我如何添加'order by product_name'？我试过这个，但结果不正确

SELECT * FROM products 
INNER JOIN product_categories on products.main_category = product_categories.id 
INNER JOIN product_sub_categories on products.sub_category = product_sub_categories.id 
WHERE products.approved = 1 AND products.main_category = 8 
ORDER BY products.product_name DESC LIMIT 0,25

但是，当添加搜索时，这会起作用

SELECT * , 
MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,product_details) 
AGAINST ('keyword') AS score FROM my_products 
INNER JOIN my_product_categories on my_products.main_category = my_product_categories.id 
INNER JOIN my_product_sub_categories on my_products.sub_category = my_product_sub_categories.id 
WHERE my_products.approved = 1 AND 
MATCH(product_name,code,tag_1,tag_2,tag_3,tag_4,tag_5,product_details) 
AGAINST('bath') ORDER BY my_products.product_name ASC LIMIT 0,25

将全文查询添加到现有查询

3 个答案: