使用PHP将数据从Mysql导出到excel

Question

我试图使用php从mysql数据库中导出我的数据。 普通数据成功导出到Excel，但图像显示不显示错误＆＃34;链接的图像无法显示。文件可能已被移动，重命名或删除。验证链接点以更正文件和位置＆＃34;。

Output of the code

source code

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<?php
// The function header by sending raw excel
header("Content-type: application/vnd-ms-excel");
 // Defines the name of the export file "codelution-export.xls"
header("Content-Disposition: attachment; filename=system_users.xls");
 // Add data table
include("config/dbconfig.php");	
?>
<!-- Image path in subfolder images -->
<img src="images/reph.png" height="115" width="730"> 
<table width=70% border="1" class="view"  align="center">

  <tr><th> No</th>
     <th> Name</th>

	<th>User Role</th>
	<th>User Name</th>
	<th>Password</th>

</class> </tr><tr> 
  <?php
$sno=1;
  $query=mysql_query("select * from users ");

  $num_rows=mysql_num_rows($query);
  if($num_rows>0)
  { while ($fields=mysql_fetch_assoc($query))
	  {	 $sno<=$num_rows; 
	  $pid=$fields['user_id'];
	  $lname=$fields['lname'];
  ?>
   <td>&nbsp; <?php echo "$sno ";
$sno++; ?></td>
<td>&nbsp; <?php echo $fields['lname']." ".$fields['fname'];?></td>
<td><?php // php code that retrieves image path from the database and prints the image
 //echo '<img width="120" height="110"  SRC="' .$fields['image'] . '" alt="Image failed to load " />'; 
 ?></td>
	<td>&nbsp; <?php echo $fields['role'];?></td>
	<td>&nbsp; <?php echo $fields['username'];?></td>

<td>&nbsp; <?php echo $fields['password'];?></td>
</tr>
  <?php
  	  }//closing the while loop
	   }//closing the if statement
	   	    echo '</table>';
?>

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