Question

有没有办法估算for循环运行多长时间？我有一个大约500,000次迭代的循环，它做了一些基本的计算，现在已经运行了一段时间。我怀疑它可能是一个永无止境的循环。

以下是代码：

mod<- function(file, level = 5){
  df<- read.csv(file = file,header = FALSE,sep = "", col.names = c("DateTime","Seq","BP1","BQ1","BO1","AP1","AQ1","AO1","BP2","BQ2","BO2","AP2","AQ2","AO2","BP3","BQ3","BO3","AP3","AQ3","AO3","BP4","BQ4","BO4","AP4","AQ4","AO4","BP5","BQ5","BO5","AP5","AQ5","AO5","BP6","BQ6","BO6","AP6","AQ6","AO6","BP7","BQ7","BO7","AP7","AQ7","AO7","BP8","BQ8","BO8","AP8","AQ8","AO8","BP9","BQ9","BO9","AP9","AQ9","AO9","BP10","BQ10","BO10","AP10","AQ10","AO10","C","Price","Qty","OldPrice","OldQty"))
  df<- df[which(df$DateTime != 0),]
  df$DateTime= as.POSIXct(df$DateTime/(10^9), origin="1970-01-01")    #timestamp conversion
  change = c()
  for(i in 2:nrow(df)){
    if(is.na(df[i,6]) == TRUE){
      change[i] = 0
      next
    } else if(is.na(df[i,63]) == TRUE){
      change[i] = 0
      next
    }
    #browser()
    if(df[i,63] == "N"){
      a = which(df[i,] == df[i,64])
      if(a[1] > 32){
        change[i] = 0
      } else if(a[1] < 32){
        change[i] = a[1]
      }
      change
    }
    #browser()
    if(df[i,63] == "C"){
      a = which(df[i,] == df[i,64])
      if(a[1] > 32){
        change[i] = 0
      }else if(a[1] < 32){
        change[i] = a[1]*-1
      }
      change
    }
    #browser()
    if(df[i,63] == "M"){
      a = which(df[i,] == df[i,64])
      b = which(df[i-1,] == df[i,66])
      if(a[1] > 32 & b[1] > 32){
        change[i] = 0
      } else if(a[1] < 32 & b[1] > 32){
        change[i] = a[1]
      } else if(a[1] < 32 & b[1] < 32){
        change[i] = b[1] - a[1]
      }
      #browser()
      change
    }
    change
  }
  change
}

我要做的是先看看第63栏（“C”）所说的内容，如果是“N”或“C”，那么请查看第64栏（“价格”）并找到它在该行中的位置，除了列64本身，然后分配列号改变[i]中。如果col63为“C”则使其为负，如果col63为“N”则为正。

如果第63列（“C”）表示“M”，则首先查看第66列（“OldPrice”）并在前一行i-1中找到它。然后在同一行中的第64列（“价格”）中找到价格并获取它们之间的差异（列数）并将其分配给更改[i]

因此输出应该是负整数或正整数的向量。

> dput(df[1:20,])
structure(list(DateTime = c(1.448855100369e+18, 1.448855100369e+18, 
1.448855100375e+18, 1.448855100376e+18, 1.448855100378e+18, 1.448855100379e+18, 
1.44885510038e+18, 1.44885510038e+18, 1.44885510038e+18, 1.448855100383e+18, 
1.448855100384e+18, 1.448855100385e+18, 1.448855100385e+18, 1.448855100385e+18, 
1.448855100386e+18, 1.448855100386e+18, 1.448855100386e+18, 1.448855100387e+18, 
1.448855100389e+18, 1.448855100389e+18), Seq = c(92L, 108L, 406L, 
479L, 643L, 722L, 811L, 822L, 828L, 1046L, 1103L, 1171L, 1186L, 
1196L, 1238L, 1249L, 1254L, 1273L, 1333L, 1343L), BP1 = c(80830L, 
80830L, 81100L, 81100L, 81100L, 81100L, 81100L, 81100L, 81100L, 
81100L, 81100L, 81100L, 81100L, 81100L, 81100L, 81100L, 81200L, 
81200L, 81200L, 81200L), BQ1 = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), BO1 = c(1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L), AP1 = c(0L, 83435L, 83435L, 82165L, 82165L, 82165L, 
82165L, 82165L, 82345L, 82345L, 82165L, 82345L, 82345L, 82165L, 
82340L, 82340L, 82340L, 82340L, 82165L, 82340L), AQ1 = c(0L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L), AO1 = c(0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), BP2 = c(0L, 0L, 80830L, 
80830L, 80830L, 80830L, 80830L, 80835L, 80835L, 80835L, 80835L, 
80835L, 80835L, 80835L, 80835L, 80835L, 81100L, 81100L, 81100L, 
81100L), BQ2 = c(0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), BO2 = c(0L, 0L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L
), AP2 = c(0L, 0L, 0L, 83435L, 83200L, 82650L, 82650L, 82650L, 
82650L, 82650L, 82650L, 82650L, 82650L, 82650L, 82650L, 82650L, 
82650L, 82650L, 82650L, 82650L), AQ2 = c(0L, 0L, 0L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), 
    AO2 = c(0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L), BP3 = c(0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 80830L, 80830L, 80830L, 80830L, 80830L, 80830L, 80830L, 
    80830L, 80830L, 80835L, 80835L, 80835L, 80835L), BQ3 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L), BO3 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), AP3 = c(0L, 
    0L, 0L, 0L, 83435L, 83200L, 83200L, 83200L, 83200L, 83200L, 
    83200L, 83200L, 82900L, 82900L, 82900L, 82900L, 82900L, 82900L, 
    82900L, 82900L), AQ3 = c(0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), AO3 = c(0L, 
    0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L), BP4 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 80830L, 80830L, 80830L, 80830L
    ), BQ4 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L), BO4 = c(0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 
    1L), AP4 = c(0L, 0L, 0L, 0L, 0L, 83435L, 83430L, 83430L, 
    83430L, 83430L, 83430L, 83430L, 83200L, 83200L, 83200L, 83200L, 
    83200L, 83200L, 83200L, 83200L), AQ4 = c(0L, 0L, 0L, 0L, 
    0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 
    2L), AO4 = c(0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), BP5 = c(0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 80035L, 
    80035L, 80035L), BQ5 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L), BO5 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 1L, 1L, 1L), AP5 = c(0L, 0L, 0L, 0L, 0L, 0L, 83435L, 
    83435L, 83435L, 83435L, 83435L, 83435L, 83430L, 83430L, 83430L, 
    83430L, 83430L, 83430L, 83430L, 83430L), AQ5 = c(0L, 0L, 
    0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L), AO5 = c(0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), BP6 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), BQ6 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), BO6 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), AP6 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 83500L, 83500L, 83500L, 83435L, 83435L, 83435L, 83435L, 
    83435L, 83435L, 83435L, 83435L), AQ6 = c(0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L), AO6 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), BP7 = c(0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L), BQ7 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), BO7 = c(0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L), AP7 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 83500L, 83500L, 83500L, 83500L, 83500L, 83500L, 
    83500L, 83500L), AQ7 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), AO7 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L), BP8 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), BQ8 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), BO8 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), AP8 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), AQ8 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), AO8 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), BP9 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), BQ9 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), BO9 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), AP9 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), AQ9 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), AO9 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), BP10 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), BQ10 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), BO10 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), AP10 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), AQ10 = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), AO10 = c(0L, 
    0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
    0L, 0L, 0L, 0L), C = structure(c(4L, 4L, 4L, 4L, 4L, 4L, 
    4L, 4L, 3L, 4L, 3L, 3L, 4L, 3L, 3L, 4L, 4L, 4L, 3L, 3L), .Label = c("", 
    "C", "M", "N"), class = "factor"), Price = c(80830L, 83435L, 
    81100L, 82165L, 83200L, 82650L, 83430L, 80835L, 82345L, 83500L, 
    82165L, 82345L, 82900L, 82165L, 82340L, 83200L, 81200L, 80035L, 
    82165L, 82340L), Qty = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), OldPrice = c(NA, 
    NA, NA, NA, NA, NA, NA, NA, 82165L, NA, 82345L, 82165L, NA, 
    82345L, 82165L, NA, NA, NA, 82340L, 82165L), OldQty = c(NA, 
    NA, NA, NA, NA, NA, NA, NA, 1L, NA, 1L, 1L, NA, 1L, 1L, NA, 
    NA, NA, 1L, 1L)), .Names = c("DateTime", "Seq", "BP1", "BQ1", 
"BO1", "AP1", "AQ1", "AO1", "BP2", "BQ2", "BO2", "AP2", "AQ2", 
"AO2", "BP3", "BQ3", "BO3", "AP3", "AQ3", "AO3", "BP4", "BQ4", 
"BO4", "AP4", "AQ4", "AO4", "BP5", "BQ5", "BO5", "AP5", "AQ5", 
"AO5", "BP6", "BQ6", "BO6", "AP6", "AQ6", "AO6", "BP7", "BQ7", 
"BO7", "AP7", "AQ7", "AO7", "BP8", "BQ8", "BO8", "AP8", "AQ8", 
"AO8", "BP9", "BQ9", "BO9", "AP9", "AQ9", "AO9", "BP10", "BQ10", 
"BO10", "AP10", "AQ10", "AO10", "C", "Price", "Qty", "OldPrice", 
"OldQty"), row.names = c(NA, 20L), class = "data.frame")

Answer 1

我将如何做到这一点。唯一需要的循环是应用which，这应该很快：

#find column matches for price
DF$change <- apply(DF[, 3:62] == DF[,64], 1, which) + 2L
#negative for C
DF$change[DF[,63] == "C"] <- DF$change[DF[,63] == "C"] * (-1)
#column matches for old price in preceding row if M
pos2 <- apply(DF[which(DF[,63] == "M") - 1, 3:62] == DF[DF[,63] == "M",66], 1, which) + 2L
#assign the difference
DF$change[DF[,63] == "M"] <- pos2 - DF$change[DF[,63] == "M"]
DF$change
#[1]  3  6  3  6 12 12 24  9  0 36  0  0 18  0  0 24  3 27  0  0

这假设始终存在匹配列。如果which返回NA，则返回which的函数中不包含integer(0)的情况。

R：循环执行时间？

1 个答案: