Question

我在下面有一些示例数据，并希望删除至少2个字符或可以说双头大写字母的所有大写字母。

HON MANI no St.Chom Chao Trapeang Thloeng Chaom Chau Dangkao 
LAY NA 35 st 70 Phum10 Boeng Salang Tuol Kouk Phnom Penh 
OK KEMEUN Ek Phnom , Battam Bang
CY VANN Rukkhak Kiri ,Battam Bang
LENG EUN , Korng Pisei , Kampong Speu
SEK HONG , Phnom Sruoch , Kampong Speu

我想在没有姓名

的情况下获得如下结果

no St.Chom Chao Trapeang Thloeng Chaom Chau Dangkao 
35 st 70 Phum10 Boeng Salang Tuol Kouk Phnom Penh 
Ek Phnom , Battam Bang
Rukkhak Kiri ,Battam Bang
,Korng Pisei , Kampong Speu
, Phnom Sruoch , Kampong Speu

请知道。

Answer 1

类似这样的事情

; with data as
(
    select  line = 'HON MANI no St.Chom Chao Trapeang Thloeng Chaom Chau Dangkao'   union all 
    select  line = 'LAY NA 35 st 70 Phum10 Boeng Salang Tuol Kouk Phnom Penh '  union all
    select  line = 'OK KEMEUN Ek Phnom , Battam Bang'   union all
    select  line = 'CY VANN Rukkhak Kiri ,Battam Bang'  union all
    select  line = 'LENG EUN , Korng Pisei , Kampong Speu'  union all
    select  line = 'SEK HONG , Phnom Sruoch , Kampong Speu'
)
select  *,
        result = case   when    first_two_word = upper(first_two_word) 
                 then   replace(line, first_two_word, '')
                 else   line 
                 end 
from    data
        cross apply
        (
            select  first_two_word = left(line, charindex(' ', line, charindex(' ', line) + 1))
        ) w

Answer 2

您可以通过创建标量值函数

来获得结果

CREATE FUNCTION dbo.getLowerCaseString(@String VARCHAR(300))
RETURNS VARCHAR(300)
AS
BEGIN

WHILE(PATINDEX('%[ABCDEFGHIJKLMNOPQRSTUVWXYZ][ABCDEFGHIJKLMNOPQRSTUVWXYZ]%',LTRIM(@String) COLLATE Latin1_General_CS_AS )>0)
BEGIN
    SET @String = STUFF(@String,PATINDEX('%[ABCDEFGHIJKLMNOPQRSTUVWXYZ][ABCDEFGHIJKLMNOPQRSTUVWXYZ]%',LTRIM(@String) COLLATE Latin1_General_CS_AS ) ,CHARINDEX(' ',LTRIM(@String)),'')   
END

RETURN @String
END
GO

调用函数

 SELECT 
    dbo.getLowerCaseString(StringColumn)
 FROM
  YourTable

从SQL Server中的字符串中删除大写字母（至少2个字符）

2 个答案: