Question

寻找以下问题的帮助以下可比较的方法，想要打印从我的Hockey Player ArrayList得分的最大目标值。我无法成功地为每个循环存储值以将其传递给可比较的方法。有什么建议我做错了吗？

public static Comparable maximum(Comparable first, Comparable second, Comparable third) {
    if (first.compareTo(second) > 0) {
        if (first.compareTo(third) > 0) {
            return first;
        }
        return third;
    } else if (second.compareTo(third) > 0) {
        return second;
    }
    return third;
}

for (HockeyPlayer hp : hockeyPlayerList){
    int first = ((HockeyPlayer) hp).getGoalsScored(); {
        first = player1;
        first = player2;
        first = player3;
        first = player4;
    }
    System.out.println("The largest string is: " + Driver.maximum(player1,player2,player3));
}

Answer 1

我普遍同意“使用java.util.Collections.sort（hockeyPlayerList）;”评论，但是如果你必须实现自己的最大值......

假设你的最终目标是能够做到这一点：

System.out.println("The largest string is: " + Driver.maximum(player1,player2,player3));

该功能可能如下所示：

public class Driver {

...

    public static Comparable maximum(Comparable... items) 
    {
        if(items.length ==  0)
        {
            return null; // no items to compare
        }

        Comparable currentMax = items[0];

        for(Comparable item : items)
        {
            // Update currentMax only if next element is larger
            currentMax = currentMax.compareTo(item) > 0 ? currentMax : item;
        }

        return currentMax;
    }
}

在Player课程中，你必须有一个toString函数打印出有关播放器的有意义信息（System.out.println将调用toString函数作为Player函数返回的maximum类。类似的东西（我给出的例子，使用你在Player函数中的实际字段）：

public class Player {

    ...
    @Override
    public String toString()
    { 
        return this.getPlayerName() + ": " + this.getGoalsScored();
    }
}

以下代码片段也没有意义：

int first = ((HockeyPlayer) hp).getGoalsScored(); {
    first = player1;
    first = player2;
    first = player3;
    first = player4;
}

不确定你想要在那里完成什么

使用Comparable

1 个答案: