Question

我知道有类似的人发布了联系表格帮助，但我遇到了问题。一切正常，但是当我提交时，我收到一封来自apache的电子邮件，显示一条空白消息。但是，当我在表单输入中使用我自己的电子邮件地址时，它可以工作。

这是我的代码

<?php 
if(isset($_POST['submit'])){}
$name = $_POST['name'];
$email = $_POST['email'];
$minrooms=$_POST['mrooms'];
$message = $_POST['comment'];
$formcontent="From: $name \n Email: $email \n Min Number of Rooms: $minrooms\n Message: $message ";
$recipient = "kellito13@gmail.com";
$subject = "Contact Form";
$mailHeader = "From: $email \r\n";
send_contact= mail($recipient, $subject, $formcontent, $mailHeader) or die("Error!");
echo "Thank You!";
}
else{
    echo"Error";
}
?>

Answer 1

您的代码中包含{}和send_contact= mail($recipient, $subject, $formcontent, $mailHeader) or die("Error!");语法错误。

它应该是这样的：

<?php
if(isset($_POST['submit'])){
    $name = $_POST['name'];
    $email = $_POST['email'];
    $minrooms=$_POST['mrooms'];
    $message = $_POST['comment'];
    $formcontent="From: $name \n Email: $email \n Min Number of Rooms: $minrooms\n Message: $message ";
    $recipient = "kellito13@gmail.com";
    $subject = "Contact Form";
    $mailHeader = "From: $email \r\n";
    $send_contact= mail($recipient, $subject, $formcontent, $mailHeader) or die("Error!");
    echo "Thank You!";
}
else{
    echo"Error";
}
?>

当我提交联系表格时，apache没有显示任何内容

1 个答案: