Question

所以我正在尝试处理以下文字。我想要的是获得一个匹配的数据，从每个班级的学分开始，并以季节和年份结束。所以对于第一堂课，它看起来像这样：

3 credits in Philosophical Perspectives
PHIL 101L
PHILOSOPHICAL PERSPECTIVES
B
3
Fall 2014

此外，我还需要获得他们仍然需要的课程。如果您发现他们在历史上缺少3个学分。这是我的文字：

3 credits in Philosophical Perspectives
PHIL 101L
PHILOSOPHICAL PERSPECTIVES
B
3
Fall 2014
Student View
3 credits in Fine Arts
ART 160L
HIST WEST ART I
B+
3
Fall 2014
3 credits in History
Still Needed:
Click here to see classes that satisfy this requirement.
3 credits in Literature
ENG 201L
INTRO LINGUISTIC
IP
(3)
Spring 2016
3 credits in Math
Still Needed:
Click here to see classes that satisfy this requirement.
3 credits in Natural Science
BIOL 225L
TOPICS IN NUTRITION
A-
3
Spring 2015
3 credits Ethics/Applied Ethics/Religious Studies
REST 209L
WORLD RELIGIONS
A-
3
Spring 2015
3 credits in Social Science
ECON 104L
PRINC MACROECONOM
T
3
Fall 2014

Answer 1

(?:^|(?<=\n))\d+\s+credits[]\s\S]*?(?=\n\d+\s+credits|$)

您可以将其与findall一起使用。请参阅演示。

https://regex101.com/r/gK9aI6/1

import re
p = re.compile(r'(?:^|(?<=\n))\d+\s+credits[]\s\S]*?(?=\n\d+\s+credits|$)')
test_str = "3 credits in Philosophical Perspectives\nPHIL 101L\nPHILOSOPHICAL PERSPECTIVES\nB\n3\nFall 2014\nStudent View\n3 credits in Fine Arts\nART 160L\nHIST WEST ART I\nB+\n3\nFall 2014\n3 credits in History\nStill Needed:\nClick here to see classes that satisfy this requirement.\n3 credits in Literature\nENG 201L\nINTRO LINGUISTIC\nIP\n(3)\nSpring 2016\n3 credits in Math\nStill Needed:\nClick here to see classes that satisfy this requirement.\n3 credits in Natural Science\nBIOL 225L\nTOPICS IN NUTRITION\nA-\n3\nSpring 2015\n3 credits Ethics/Applied Ethics/Religious Studies\nREST 209L\nWORLD RELIGIONS\nA-\n3\nSpring 2015\n3 credits in Social Science\nECON 104L\nPRINC MACROECONOM\nT\n3\nFall 2014"

re.findall(p, test_str)

Answer 2

你可以组合一个非贪婪的“任何”序列，并使用每组最后一行的已知结构将它们解析成块：

/((?:.\n?)*?(?:Fall|Summer|Spring|Winter)\s\d{4})/g

(?:.\n?)*? - 吃任何字符（可能后面有换行符）一次
然后只需匹配结束序列：(?:Fall|Summer|Spring|Winter)\s\d{4}

See the demo here并注意每个赠送金额实际上都是单正则表达式匹配。

Answer 3

尝试以下代码段：

import re

courses = r"....your...content"

rx = re.compile(r"\d+.*?(?:FALL|SPRING)\s*\d{4}", re.IGNORECASE | re.DOTALL)
for course in rx.finditer(courses):
    print(course.group())
    print("----------------------------\n")

如果courses包含您的示例内容，则输出为：

3 credits in Philosophical Perspectives
PHIL 101L
PHILOSOPHICAL PERSPECTIVES
B
3
Fall 2014
----------------------------

3 credits in Fine Arts
ART 160L
HIST WEST ART I
B+
3
Fall 2014
----------------------------

3 credits in History
Still Needed:
Click here to see classes that satisfy this requirement.
3 credits in Literature
ENG 201L
INTRO LINGUISTIC
IP
(3)
Spring 2016
----------------------------

... omitting rest....

具有多行的正则表达式

3 个答案: