如何检查时间是否重叠?

时间:2016-03-13 06:58:00

标签: java android datetime time overlap

我创建了一个活动。现在我想检查它们是否相互重叠。我在数据库中以日期格式存储了startTime和endTime。

现在我想检查事件的时间是否重叠。为此,我想要获取所有事件startTime和endTime,从日期检索小时和分钟,然后将小时和分钟与当前小时和分钟进行比较。

日期格式是这样的:df = new SimpleDateFormat(“E MMM dd HH:mm:ss zzzz yyyy”);

我首先尝试通过查询比较两个日期,但这并没有帮助。如果事件当时不存在,那么有时它也会返回true。

我的第一次尝试是:

public int returnCount(String startTime, String endTime, String day)
{
    String selectQuery = "SELECT COUNT(*) FROM " + TABLE + " WHERE " + KEY_DAY_OF_WEEK + " = '" + day + "'" + " AND "

            + "(" + KEY_FROM_DATE + " <= '" + startTime
            + "' AND '" + startTime + "' <= " + KEY_TO_DATE + ") OR "

            + " (" + KEY_FROM_DATE + " <= '" + endTime
            + "' AND '" + endTime + "' <= " + KEY_TO_DATE + ") OR "

            + " (" + KEY_FROM_DATE + " <= '" + startTime
            + "' AND '" + endTime + "' <= " + KEY_TO_DATE + ") OR "

            + " (" + KEY_FROM_DATE + " <= '" + endTime
            + "' AND '" + startTime + "' <= " + KEY_FROM_DATE + ") OR "

            + " (" + KEY_TO_DATE + " <= '" + startTime
            + "' AND '" + endTime + "' <= " + KEY_TO_DATE + ") OR "

            + " ('" + startTime + "' < " + KEY_FROM_DATE
            + " AND " + KEY_TO_DATE + " < '" + endTime + "')";

    SQLiteDatabase db = this.getWritableDatabase();
    Cursor mCount= db.rawQuery(selectQuery,null);

    if (mCount.moveToFirst()) {
        do {
            EventData event = new EventData();
            count = mCount.getInt(0);
        } while (mCount.moveToNext());
    }

    Log.d("query",selectQuery);

    Log.d("count",String.valueOf(count));
    mCount.close();

    return count;

}

所以现在我想做出改变并比较小时和分钟。为此,我的尝试是将小时和分钟转换为字符串,然后进行比较,但它没有帮助。

 public void checkOverlappingEvents()
{

    List<EventData> checkOverlappingEvents = new ArrayList<>();

    EventTableHelper eventTableHelper = new EventTableHelper(AddEventActivity.this);


    checkOverlappingEvents = eventTableHelper.getAllEvents("Mon");


    for (EventData e : checkOverlappingEvents)
    {

        df = new SimpleDateFormat("E MMM dd HH:mm:ss zzzz yyyy");

        Date checkFromDate = new Date();
        Date checkToDate = new Date();


        try {

            checkFromDate = df.parse(e.getFromDate());
            checkToDate = df.parse(e.getToDate());

        } catch (ParseException ex) {

        }


        int startHours = datefrom.getHours();
        int endHours = dateto.getMinutes();

        String startTime = checkFromDate.getHours() + ":" + checkFromDate.getMinutes();
        String endTime = checkToDate.getHours() + ":" + checkToDate.getMinutes();

        String startDate = datefrom.getHours() + ":" + datefrom.getMinutes();
        String endDate = dateto.getHours() + ":" + dateto.getMinutes();

        if(startTime.equals(startDate) && endTime.equals(endDate))
        {
            overlapEvents = true;
        }

    }

}

getAllEvents查询:

 public List<EventData> getAllEvents(String day) {
    List<EventData> conList = new ArrayList<EventData>();

    String selectQuery = "SELECT  * FROM " + TABLE + " WHERE " + KEY_DAY_OF_WEEK + " = '" + day + "'";

    SQLiteDatabase db = this.getWritableDatabase();
    Cursor cursor = db.rawQuery(selectQuery, null);

    if (cursor.moveToFirst()) {
        do {

            EventData event = new EventData();

            event.setId(Integer.parseInt(cursor.getString(0)));
            event.setTitle(cursor.getString(1));
            event.setFromDate(cursor.getString(2));
            event.setToDate(cursor.getString(3));
            event.setDayOfWeek(cursor.getString(4));
            event.setLocation(cursor.getString(5));
            event.setNotificationTime(cursor.getString(6));
            event.setTableId(Integer.parseInt(cursor.getString(7)));
            event.setNotificationId(Integer.parseInt(cursor.getString(8)));
            event.setNotification(cursor.getString(9));



            conList.add(event);
        } while (cursor.moveToNext());
    }

    return conList;
}

编辑:

public void checkOverlappingEvents()
{

    List<EventData> checkOverlappingEvents = new ArrayList<>();

    EventTableHelper eventTableHelper = new EventTableHelper(AddEventActivity.this);


    checkOverlappingEvents = eventTableHelper.getAllEvents("Mon");


    for (EventData e : checkOverlappingEvents)
    {

        df = new SimpleDateFormat("E MMM dd HH:mm:ss zzzz yyyy");

        Date checkFromDate = new Date();
        Date checkToDate = new Date();


        try {

            checkFromDate = df.parse(e.getFromDate());
            checkToDate = df.parse(e.getToDate());

        } catch (ParseException ex) {

        }

checkToDate.getMinutes();

        if(datefrom.compareTo(checkToDate) == checkFromDate.compareTo(dateto))
        {
            overlapEvents = true;
        }

    }

}

我这样做了,所以它适用于添加新事件。检查其他日期是否重叠或不重叠,但我也想更新活动。

如果我使用相同的功能并且仅更改现有事件的结束时间,那么当开始时间相同时,它始终显示事件存在。如何在进行事件更新时进行比较?

任何人都可以帮助我如何将小时和分钟与当前小时和分钟进行比较?

2 个答案:

答案 0 :(得分:1)

我会使用Date对象

Date startDate1 = ...
Date startDate2 = ...
Date endDate1 = ...
Date endDate2 = ...

boolean overlapping = datesOverlap(startDate1, endDate1, startDate2, endDate2);

private boolean datesOverlap(Date startDate1, endDate1, startDate2, endDate2){
    return startDate1.before(endDate2) && startDate2.before(endDate1);
}

答案 1 :(得分:0)

我建议您将字符串startTimeendTime转换为Date个对象,并使用date1.compareTo(date2),如果1则返回date2发生在-1之前,0同一时间。所以你会有类似的东西:

if(start1.compareTo(start2) != end1.compareTo(start2)) /*overlaps*/;  

您可以看到它的可视化效果:

start1--------start2------end1--------end2  → will return true
start1--------end1------start2--------end2  → will return false  

注意,这会计算范围在另一个停止为重叠时正好开始的情况。如果您不这样做,您应该处理开始与另一端相同的情况