如果对表单URL的ajax调用失败,我试图在表单中呈现错误。以下是我的Admin
组件:
#app/assets/javascripts/components/admin.js.coffee
@Admin = React.createClass
# propTypes: ->
# emailVal: React.PropTypes.string.isRequired
getInitialState: ->
edit: false
errorTexts: []
handleToggle: (e) ->
e.preventDefault()
@setState edit: !@state.edit
@setState errorTexts: []
handleDelete: (e) ->
e.preventDefault()
# yeah... jQuery doesn't have a $.delete shortcut method
$.ajax
method: 'DELETE'
url: "/admins/#{ @props.admin.id }"
dataType: 'JSON'
success: () =>
@props.handleDeleteAdmin @props.admins
handleEdit: (e) ->
e.preventDefault()
data = email: ReactDOM.findDOMNode(@refs.email).value
# jQuery doesn't have a $.put shortcut method either
$.ajax
method: 'PUT'
async: false
url: "/admins/#{ @props.admin.id }"
dataType: 'JSON'
data:
admin: data
error: (data, status, xhr) =>
errorTexts = []
for key, value of data.responseJSON
errorText = "#{key} #{value.toString()}"
errorTexts.push errorText
@replaceState errorTexts: errorTexts
@setState edit: true
success: (data, status, xhr) =>
@setState edit: false
@props.handleEditAdmin @props.admin, data
adminRow: ->
dom.tr null,
dom.td null, @props.admin.email
dom.td null,
dom.a
className: 'btn btn-default'
onClick: @handleToggle
'Edit'
dom.a
className: 'btn btn-danger'
onClick: @handleDelete
'Delete'
adminForm: ->
dom.tr null,
dom.td null,
dom.input
className: 'form-control'
type: 'text'
defaultValue: @props.admin.email
ref: 'email'
for errorText, index in @state.errorTexts
React.createElement AdminError, key: index, errorText: errorText
dom.td null,
dom.a
className: 'btn btn-default'
onClick: @handleEdit
'Update'
dom.a
className: 'btn btn-danger'
onClick: @handleToggle
'Cancel'
render: ->
if @state.edit
@adminForm()
else
@adminRow()
相应的AdminError
组件是:
#app/assets/javascripts/components/adminerror.js.coffee
@AdminError = React.createClass
getDefaultProps: ->
errorText: ""
render: ->
dom.div
className: 'help-block'
@props.errorText
调试时我得到@ props.errorText的正确值为“email is invalid”。但它没有在页面上呈现,我在控制台中发出警告:“警告:输入是一个void元素标记,不能有children
或使用props.dangerouslySetInnerHTML
。检查render方法为null “。
附件是错误和页面的屏幕截图。
我尝试按如下方式更改AdminError组件,但它不起作用:
#app/assets/javascripts/components/adminerror.js.coffee
@AdminError = React.createClass
getDefaultProps: ->
errorText: ""
render: ->
dom.div
className: 'help-block'
dangerouslySetInnerHTML: __html: marked(@props.errorText.toString(), {saitize: true})
当我在返回dangerouslySetInnerHTML的行设置调试点时,我正确地将@props.errorText
的值设为“电子邮件无效”,将marked(@props.errorText.toString())
的值设为“
电子邮件无效
“..但仍然没有呈现错误的帮助块。
更新 在AdminError组件中进行了以下更改
@AdminError = React.createClass
getDefaultProps: ->
# errorText: ""
errorTexts: []
render: ->
for errorText in @props.errorTexts
dom.div
className: 'help-block'
errorText
并在Admin组件中对adminform方法进行了以下更改:
if(@state.errorTexts.length>0)
dangerouslySetInnerHTML: {
__html: ReactDOMServer.renderToString(
# for errorText, index in @state.errorTexts
React.createElement AdminError, errorTexts: @state.errorTexts
)
}
不再收到警告,而是收到以下错误:
Uncaught Invariant Violation: ReactCompositeComponent.render(): A valid ReactComponent must be returned. You may have returned undefined, an array or some other invalid object.
答案 0 :(得分:7)
警告:input是一个void元素标记,不能有
children
...
dom.input
可能没有子元素。
但是这段代码试图将错误消息呈现为dom.input
的孩子:
dom.td null,
dom.input
className: 'form-control'
type: 'text'
defaultValue: @props.admin.email
ref: 'email'
# These are being rendered as children of the input:
for errorText, index in @state.errorTexts
React.createElement AdminError, key: index, errorText: errorText
您可以在其他地方呈现这些错误消息吗?例如,作为输入的兄弟姐妹:
dom.td null,
dom.input
className: 'form-control'
type: 'text'
defaultValue: @props.admin.email
ref: 'email'
for errorText, index in @state.errorTexts
React.createElement AdminError, key: index, errorText: errorText