我想要做的是onLoad本质上,找到每个td的所有id,其编号为1-7,并将其替换为与该编号对应的图像,即
<td id="7" class="level">7</td>
会将7,内容更改为......
<td id="7" class="level"><img src="../img/CL7.png" alt=""></td>
所以我到目前为止的内容如下:
$(document).ready(function()
{
$("td").click(function()
{
var findID =$(this).attr('id');
var replace ="<img src=\"../img/cl"+ findID +".png\" alt=''>";
function ReplaceCellContent(findID, replace)
{
return $("tbody tr td.level:contains('" + findID + "')").html(replace);
}
var myStringArray = [1,2,3,4,5,6,7];
var arrayLength = myStringArray.length;
for (var i = 0; i < arrayLength; i++) {
ReplaceCellContent(findID, replace);
}
});
});
所以它会去,找到每个td的td的所有ID。我希望它对页面加载时的1-7范围内的所有ID执行此操作。
我对JQuery / JavaScript有些新手,我通过GOOGLE FYI得到了与JQUERY API相关的脚本链接,所以任何解释都会受到高度赞赏。我试图使用底部的循环来遍历所有可能的数字,然后将它们插入但我无法想到如何连接每个具有该ID的原始td。 / p>
JQuery需要更改的HTML表格如下所示,写出:
<table class="sortable">
<thead>
<tr>
<th>Player Name</th>
<th>Level</th>
</tr>
</thead>
<tbody>
<tr>
<td>Krack</td>
<td id="7" class="level">7</td>
</tr>
<tr>
<td>Lively</td>
<td id="6" class="level">6</td>
</tr>
<tr>
<td>Bamon Williams</td>
<td id="6" class="level">6</td>
</tr>
<tr>
<td>Sinister Char</td>
<td id="5" class="level">5</td>
</tr>
<tr>
<td>Senior BoomBox</td>
<td id="5" class="level">5</td>
</tr>
<tr>
<td>Blitzking</td>
<td id="4" class="level">4</td>
</tr>
<tr>
<td>Hadooooken</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>Jumpman2392</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>ALEC*</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>Frokido</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>B. McOxbig</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>[MES] Koko</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>PinkStrank</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>papa von</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>Nuski</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>LunchBoxes</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>Grenade65</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>[MGS]TOAD</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>NoahS</td>
<td id="1" class="level">1</td>
</tr>
</tbody>
<tfoot></tfoot>
</table>
答案 0 :(得分:1)
jQuery很棒,但我并不推荐它用于所有内容,特别是在你真正了解JavaScript之前,所以这个解决方案只使用jQuery来注册一个在页面准备好进行交互时调用的函数:
locationManager = [[CLLocationManager alloc]init];
locationManager.delegate = self;
locationManager.desiredAccuracy = kCLLocationAccuracyBest;
locationManager.distanceFilter = 1000.0f;
[locationManager requestAlwaysAuthorization];
[locationManager requestWhenInUseAuthorization];
[locationManager startUpdatingLocation];
这是一个工作小提琴:https://jsfiddle.net/96hkhy4j/4/
答案 1 :(得分:1)
你可能会做这样的事情
$(document).ready(function() {
var myStringArray = [1,2,3,4,5,6,7];
for (var i = 1; i <= myStringArray.length; i++) {
var findID = i;
var replace ="<img src=\"../img/cl"+ findID +".png\" alt=''>";
ReplaceCellContent(findID, replace);
}
function ReplaceCellContent(findID, replace) {
return $("tbody tr td.level:contains('" + findID + "')").html(replace);
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="sortable">
<thead>
<tr>
<th>Player Name</th>
<th>Level</th>
</tr>
</thead>
<tbody>
<tr>
<td>Krack</td>
<td id="7" class="level">7</td>
</tr>
<tr>
<td>Lively</td>
<td id="6" class="level">6</td>
</tr>
<tr>
<td>Bamon Williams</td>
<td id="6" class="level">6</td>
</tr>
<tr>
<td>Sinister Char</td>
<td id="5" class="level">5</td>
</tr>
<tr>
<td>Senior BoomBox</td>
<td id="5" class="level">5</td>
</tr>
<tr>
<td>Blitzking</td>
<td id="4" class="level">4</td>
</tr>
<tr>
<td>Hadooooken</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>Jumpman2392</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>ALEC*</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>Frokido</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>B. McOxbig</td>
<td id="2" class="level">2</td>
</tr>
<tr>
<td>[MES] Koko</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>PinkStrank</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>papa von</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>Nuski</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>LunchBoxes</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>Grenade65</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>[MGS]TOAD</td>
<td id="1" class="level">1</td>
</tr>
<tr>
<td>NoahS</td>
<td id="1" class="level">1</td>
</tr>
</tbody>
<tfoot></tfoot>
</table>
答案 2 :(得分:1)
只需用第3行代替第3行。
$(document).ready(function()
{
$("tbody td").each(function()
{
var findID =$(this).attr('id');
var replace ="<img src=\"../img/cl"+ findID +".png\" alt=''>";
function ReplaceCellContent(findID, replace)
{
return $("tbody tr td.level:contains('" + findID + "')").html(replace);
}
var myStringArray = [1,2,3,4,5,6,7];
var arrayLength = myStringArray.length;
for (var i = 0; i < arrayLength; i++) {
ReplaceCellContent(findID, replace);
}
});
});
答案 3 :(得分:0)
您好,您只需添加jQuery并尝试这种方式
<script src="jquery-2.2.1.min.js"></script>
<script>
$('table tr td:nth-child(2)').each(function() {
var id =$(this).attr('id');
$(this).html('<img src="../img/CL'+id+'.png" alt="">')
});
</script>