Question

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int guessGame(int guessed_num){
    int counter = 0;
    int random_num = 0;

 while(1)
    {
        counter++;
        if (guessed_num == random_num)
        {
            printf("Correct! That's the number.\n", counter);
            break;
        }

        if (guessed_num < random_num)
            printf("Too low. Guess again.\n");

        if (guessed_num > random_num)
            printf("Too high. Guess again.\n");

    }

}

int main(){

int guessed_num = 0;


srand(time(NULL));
int random_num = rand() % 50 + 1;

printf("I have a number between 1-50.\n");
printf("Can you guess what it is?\n");
printf("Enter your initial guess.\n");

        scanf("%d", &guessed_num);
        printf("%d\n" ,guessGame(guessed_num));


return 0;
}

所以我必须做一个猜谜游戏，用户必须正确猜测一个随机创建的整数。问题是，我必须使用一个函数来运行实际的猜谜游戏。我被卡住了，因为我不知道如何正确调用我的功能。我知道我的main函数中的printf语句不是正确的方法。

Answer 1

由于您只想打印猜测状态（太高，太低等），具体取决于用户输入的单个参数，因此您无需在功能中使用while循环。以下代码将有所帮助：

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
#include<time.h>

int random_num;
void guessGame(int guessed_num){


if (guessed_num == random_num)
    printf("Correct! That's the number.\n", guessed_num);
else
    if (guessed_num < random_num)
        printf("Too low. Guess again.\n");
    else
        printf("Too high. Guess again.\n");
}

int main(){

int guessed_num = 0;
srand(time(NULL));
random_num = rand() % 50 + 1;

printf("I have a number between 1-50.\n");
printf("Can you guess what it is?\n");
while(1){
printf("Enter your initial guess.\n");

    scanf("%d", &guessed_num);
    guessGame(guessed_num);
}

return 0;
}

如何调用一个C函数，它只是根据参数打印出一个语句

1 个答案: