Question

连接蓝牙设备的正常方法是配对。

我们需要以异常方式连接设备：仅使用蓝牙MAC地址。我们不希望系统提示输入PIN码。

我们知道该设备支持这种技术，但我们无法在Android上找到这种方法。

缩写代码如下所示：

  String mac_address = “00:11:22:33:44:55”
  BluetoothAdapter mBluetoothAdapter = BluetoothAdapter.getDefaultAdapter();

  BluetoothDevice bluetoothDevice = mBluetoothAdapter.getRemoteDevice(mac_address);

  Method m = bluetoothDevice.getClass().getMethod("createRfcommSocket", 
           new Class[] {int.class});
  BluetoothSocket socket = (BluetoothSocket) m.invoke(device, 1);

  socket.connect();

问题是，在socket.connect()时，系统会提示我们输入个人识别码。此设备不需要PIN，因此我们不希望系统提示输入PIN。

我们不需要知道PIN的原因：

我们制造此设备并编写固件。
我们可以使用C＃编写的Windows程序连接到它。

我们如何修改代码，使其不会提示输入PIN码？

[编辑以测试评论中的建议]

我们测试了方法createInsecureRfcommSocketToServiceRecord，如下所示：

ParcelUuid list[] = device.getUuids();
BluetoothSocket  socket = bluetoothDevice.createInsecureRfcommSocketToServiceRecord(list[0].getUuid());

然后我们得到这样的错误：

I/InputDispatcher(  382): Delivering touch to current input target: action: 0x1
I/InputDispatcher(  382): Delivering touch to current input target: action: 0x1
V/BluetoothSocket.cpp(16956): initSocketNative
V/BluetoothSocket.cpp(16956): ...fd 66 created (RFCOMM, lm = 0)
V/BluetoothSocket.cpp(16956): initSocketFromFdNative
I/BluetoothPolicyService(  382): getBluetoothDataTransferAllowed
D/BluetoothUtils(16956): isSocketAllowedBySecurityPolicy start : device null
V/BluetoothService.cpp(  382): createDeviceNative
V/BluetoothService.cpp(  382): ... address =
V/BluetoothEventLoop.cpp(  382): onCreateDeviceResult
V/BluetoothEventLoop.cpp(  382): onCreateDeviceResult
E/BluetoothEventLoop.cpp(  382): onCreateDeviceResult: D-Bus error: org.bluez.Error.AlreadyExists (Already Exists)
D/BluetoothEventLoop(  382): Result of onCreateDeviceResult:1
V/BluetoothService.cpp(  382): discoverServicesNative
V/BluetoothService.cpp(  382): ... Object Path = /org/bluez/1100/hci0/dev_00_11_22_33_44_55
V/BluetoothService.cpp(  382): ... Pattern = , strlen = 0
D/FStest  (  633): check default
D/FStest  (  633): check default

Answer 1

这绝对有可能。您应该在以下位置查看Android BluetoothChat演示应用：http://developer.android.com/samples/BluetoothChat/src/com.example.android.bluetoothchat/BluetoothChatService.html 他们使用不安全的渠道：

public ConnectThread(BluetoothDevice device, boolean secure) {
    mmDevice = device;
    BluetoothSocket tmp = null;
    mSocketType = secure ? "Secure" : "Insecure";

    // Get a BluetoothSocket for a connection with the
    // given BluetoothDevice
    try {
        if (secure) {
            tmp = device.createRfcommSocketToServiceRecord(
                    MY_UUID_SECURE);
        } else {
            tmp = device.createInsecureRfcommSocketToServiceRecord(
                    MY_UUID_INSECURE);
        }
    } catch (IOException e) {
        Log.e(TAG, "Socket Type: " + mSocketType + "create() failed", e);
    }
    mmSocket = tmp;
}

在客户端。在服务器端：

  public AcceptThread(boolean secure) {
            BluetoothServerSocket tmp = null;
            mSocketType = secure ? "Secure" : "Insecure";

            // Create a new listening server socket
            try {
                if (secure) {
                    tmp = mAdapter.listenUsingRfcommWithServiceRecord(NAME_SECURE,
                            MY_UUID_SECURE);
                } else {
                    tmp = mAdapter.listenUsingInsecureRfcommWithServiceRecord(
                            NAME_INSECURE, MY_UUID_INSECURE);
                }
            } catch (IOException e) {
                Log.e(TAG, "Socket Type: " + mSocketType + "listen() failed", e);
            }
            mmServerSocket = tmp;
        }

请注意，您需要蓝牙MAC地址。谷歌试图隐藏地址并使其无法使用（以防止跟踪）。您在获取自己的MAC地址时遇到问题，远程设备的MAC地址会随机化并在一段时间后发生变化：http://developer.android.com/about/versions/marshmallow/android-6.0-changes.html#behavior-hardware-id

蓝牙连接无需配对

1 个答案: