Question

if(idExists($id)) {
    print 'value was true';
} else {
    print 'value was false';
}

大家好，你可以看到回声即将显示Loged会员下载的图片。但我不知道如何创建循环，我可以显示每个图片成员下载？所有该数据库都有ID，MemberID和Pcuture名称。例如，回显每个具有成员ID 2的图片。我应该使用JOIN吗？

Answer 1

您将mysqli_fetch_assoc置于while循环中。

<?php require('includes/config.php');
include("includes/conf_proc.php");

//if not logged in redirect to login page
if(!$user->is_logged_in()){ header('Location: login.php'); }

//define page title
$title = 'Account Page';

//include header template
require('layout/header.php'); 

$img_query = "SELECT * FROM `images` WHERE memberID='".$_SESSION['memberID']."'";
$img = mysqli_query($conn, $img_query);
$num_row = mysqli_num_rows($img);


?>
    <div class="container">

    <h2 style="margin-bottom:10px;margin-left:15px;">User account</h2>
    <?php
    while($rows = mysqli_fetch_assoc($img))
    {
    ?>
        <div class="row" style="background-color: white;">
            <div class="col-sm-6 col-md-12" style="margin-top:20px; margin-left:90px">
                <?php
                    echo '<img src="./demo/covers/'.$rows['image'].'" />';
                    echo $num_row;
                ?>
            </div>
        </div>
    <?php 
    }
    ?>
    </div>
//include header template
require('layout/footer.php'); 
?>

回应每个图像的会员ID

1 个答案: