php在弹出窗口中显示特定数据

时间：2016-03-11 18:02:28

标签： php mysql

我创建了一个在线注册系统。我已经制作了一份无序列表，以显示等待批准或拒绝的新待审申请人。我还为每个新申请人添加了一个按钮，以显示待处理表中的数据。

问题是当我添加多个申请人时，它只会显示所有申请人的最后申请人详细信息。我已经经历了好几个小时，但几天没有任何作用。

这是我的代码来自具有无序列表的页面：

function getStudent () {
        global $conn;
        $query = "SELECT * FROM pending_students_table WHERE status IS NULL;";
        $result = mysqli_query($conn, $query);

        $i = 1;

        while ($row = mysqli_fetch_array($result)) {
        $sId = $row['id'];
        $sName = $row['student_name'];
        $_SESSION['id'] = $row['id'];

        echo "<tr id='sNew".$i."'>";
        echo "<td>".$i." - </td>";
        echo "<td>{$sName}</td>";
        echo "<td><button type='submit' name='sAcc' value='{$sId}'>Accept</button></td>";
        echo "<td><button type='submit' name='sRej' value='{$sId}'>Reject</button></td>";
        echo "<td><button name='stInfo' value='{$sId}'><a href='student_information.php?id=<?php echo ".'"$row[$id]"'."; ?>' target='_blank' style='color: #000000; text-decoration: none;' onClick='pop_up(this)'>Student Details</a></button></td>";
        echo "</tr>";

        $i++;
        }


}

这是来自student_information.php的代码：

<?php
session_start();
include ('partials/connectDb.php');

echo "<h2>Student Information</h2>";

$id = $_SESSION['id'];
$sql = "SELECT pending_students_table.id, pending_students_table.student_name,
        pending_students_table.student_email, pending_students_table.student_phone,
        major_table.major_name, pending_students_table.student_password,
        pending_students_table.high_school_major, pending_students_table.high_school_gpa,
        pending_students_table.adviser, pending_students_table.status 
        FROM pending_students_table INNER JOIN major_table ON pending_students_table.student_major = major_table.major_id WHERE pending_students_table.id = '$id';";
$result = mysqli_query($conn, $sql);

while($row = mysqli_fetch_array($result)) {
    $sId = $row['id'];
    $sName = $row['student_name'];
    $sPhone = $row['student_phone'];
    $sMajor = $row['major_name'];
    $sHsMajor = $row['high_school_major'];
    $sHsGpa = $row['high_school_gpa'];

    $sHsMajorString = '';

    if ($sHsMajor == 1) {
        $sHsMajorString = 'Commercial';
    } elseif ($sHsMajor == 2) {
        $sHsMajorString = 'Literature';
    } elseif ($sHsMajor == 3) {
        $sHsMajorString = 'Science';
    } elseif ($sHsMajor == 4) {
        $sHsMajorString = '(Institute of Technology)';
    }

    echo "<ul>";
    echo "<li>Name: {$sName}</li>";
    echo "<li>Phone: {$sPhone}</li>";
    echo "<li>Selected Major: {$sMajor}</li>";
    echo "<li>High School Major: {$sHsMajorString}</li>";
    echo "<li>High School GPA: {$sHsGpa}</li>";
    echo "</ul>";


}
?>

3 个答案:

答案 0 :(得分：0)

您在students_information.php中使用$ _SESSION ['id']，这始终是最后查询的学生。

解决方案：

使用$ _GET变量：

$id = $_GET['id'];

第二个问题：

创建链接时，添加另一对不需要的链接。所以要么按照我的评论中的建议替换它们，要么使用

str_replace("'","")

答案 1 :(得分：0)

在您对student_information.php的链接中，您使用内联PHP代码，但您已经在解析区域中。 因此，您不必使用href='student_information.php?id=<?php echo ".'"$row[$id]"'."; ?>' target='_blank'，即可使用href='student_information.php?id=$row['id']' target='_blank'。

更改代码：

function getStudent () {
        global $conn;
        $query = "SELECT * FROM pending_students_table WHERE status IS NULL;";
        $result = mysqli_query($conn, $query);

        $i = 1;

        while ($row = mysqli_fetch_array($result)) {
        $sId = $row['id'];
        $sName = $row['student_name'];
        $_SESSION['id'] = $row['id'];

        echo "<tr id='sNew".$i."'>";
        echo "<td>".$i." - </td>";
        echo "<td>{$sName}</td>";
        echo "<td><button type='submit' name='sAcc' value='{$sId}'>Accept</button></td>";
        echo "<td><button type='submit' name='sRej' value='{$sId}'>Reject</button></td>";
        echo "<td><button name='stInfo' value='{$sId}'><a href='student_information.php?id=".$row['id']."' target='_blank' style='color: #000000; text-decoration: none;' onClick='pop_up(this)'>Student Details</a></button></td>";
        echo "</tr>";

        $i++;
        }


}

此外，您应该使用$id = $_GET['id'];代替$id = $_SESSION['id'];，因为$_SESSION['id'];将始终包含最后一个ID。

更改代码：

<?php
session_start();
include ('partials/connectDb.php');

echo "<h2>Student Information</h2>";

$id = $_GET['id'];

$sql = "SELECT pending_students_table.id, pending_students_table.student_name,
        pending_students_table.student_email, pending_students_table.student_phone,
        major_table.major_name, pending_students_table.student_password,
        pending_students_table.high_school_major, pending_students_table.high_school_gpa,
        pending_students_table.adviser, pending_students_table.status 
        FROM pending_students_table INNER JOIN major_table ON pending_students_table.student_major = major_table.major_id WHERE pending_students_table.id = '$id';";
$result = mysqli_query($conn, $sql);

while($row = mysqli_fetch_array($result)) {
    $sId = $row['id'];
    $sName = $row['student_name'];
    $sPhone = $row['student_phone'];
    $sMajor = $row['major_name'];
    $sHsMajor = $row['high_school_major'];
    $sHsGpa = $row['high_school_gpa'];

    $sHsMajorString = '';

    if ($sHsMajor == 1) {
        $sHsMajorString = 'Commercial';
    } elseif ($sHsMajor == 2) {
        $sHsMajorString = 'Literature';
    } elseif ($sHsMajor == 3) {
        $sHsMajorString = 'Science';
    } elseif ($sHsMajor == 4) {
        $sHsMajorString = '(Institute of Technology)';
    }

    echo "<ul>";
    echo "<li>Name: {$sName}</li>";
    echo "<li>Phone: {$sPhone}</li>";
    echo "<li>Selected Major: {$sMajor}</li>";
    echo "<li>High School Major: {$sHsMajorString}</li>";
    echo "<li>High School GPA: {$sHsGpa}</li>";
    echo "</ul>";


}
?>

答案 2 :(得分：0)

根据您的问题，我认为仅仅为了批准或拒绝而发送用户会话是不明智的。这可能会使您的数据库容易批准或拒绝错误的结果，因为在某些情况下您可能会忘记取消设置会话。

我建议您使用 $ _ POST 或 $ _ GET 。

例如在你的问题中，我会改变

此$id = $_SESSION['id'];在student_information.php页面中显示为$id = $_GET['id'];

并在链接中更正您的代码，部分代码不正确

例如，在你的代码中，我看到你回应了另一个不推荐的回声，而且你还在另一个语法<?php中添加了另一个<?php语法，也不推荐。

即。这一行

echo "<td><button name='stInfo' value='{$sId}'><a href='student_information.php?id=<?php echo ".'"$row[$id]"'."; ?>' target='_blank' style='color: #000000; text-decoration: none;' onClick='pop_up(this)'>Student Details</a></button></td>";

尝试替换此部分

<a href='student_information.php?id=<?php echo ".'"$row[$id]"'."; ?>...

这样的事情

<a href='student_information.php?id=".$sId.".....

在您的student_informtion.php页面中。由于您只显示一个学生，我没有看到尝试显示列表的原因。即这部分

while($row = mysqli_fetch_array($result)) {....

希望这会有所帮助

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