我试图用字符串替换所有非单词字符,空字符串期望空格,并将所有多个空格放在一起作为一个单独的空格。
以下代码执行此操作。
$cleanedString = preg_replace('/[^\w]/', ' ', $name);
$cleanedString = preg_replace('/\s+/', ' ', $cleanedString);
但是当我尝试使用mb_ereg_replace时,没有任何反应。
$cleanedString = mb_ereg_replace('/[^\w]/', ' ', $name);
$cleanedString = mb_ereg_replace('/\s+/', ' ', $cleanedString);
$ cleaningString与上述情况下的$ name相同。我做错了什么?
答案 0 :(得分:10)
mb_ereg_replace
不使用分隔符。您可能也可能不必在之前指定编码。
mb_regex_encoding("UTF-8");
//regex could also be \W
$cleanedString = mb_ereg_replace('[^\w]', ' ', $name);
$cleanedString = mb_ereg_replace('\s+', ' ', $cleanedString);
答案 1 :(得分:-1)
function create_slug_html($string, $ext='.html'){
$replace = '-';
$string=strtolower($string);
$string=trim($string);
mb_regex_encoding("UTF-8");
//regex could also be \W
$string= mb_ereg_replace('[^\w]', ' ', $string);
$string= mb_ereg_replace('\s+', ' ', $string);
//remove query string
if(preg_match("#^http(s)?://[a-z0-9-_.]+\.[a-z]{2,4}#i",$string)){
$parsed_url = parse_url($string);
$string = $parsed_url['host'].' '.$parsed_url['path'];
//if want to add scheme eg. http, https than uncomment next line
//$string = $parsed_url['scheme'].' '.$string;
}
//replace / and . with white space
$string = preg_replace("/[\/\.]/", " ", $string);
// $string = preg_replace("/[^a-z0-9_\s-]/", "", $string);
//remove multiple dashes or whitespaces
$string = preg_replace("/[\s-]+/", " ", $string);
//convert whitespaces and underscore to $replace
$string = preg_replace("/[\s_]/", $replace, $string);
//limit the slug size
$string = substr($string, 0, 200);
//slug is generated
return ($ext) ? $string.$ext : $string;
}
请检查它是否正常并支持英语和unicode
答案 2 :(得分:-3)
输入不是Multi-Byte,因此mb
函数失败。