Question

我想在codeigniter中打印geolocation API中的所有信息，然后我想插入数据库。我尝试使用foreach打印但发现错误，

    $ip='202.6x.xx.xx';
    $this->load->library('Geolocation');
    $this->load->config('geolocation', true);
    $config = $this->config->config['geolocation'];
    $this->geolocation->initialize($config);
    $this->geolocation->set_ip_address($ip);
    $country = $this->geolocation->get_country();
    //var_dump($country);

    $city = $this->geolocation->get_city();
    if($city === FALSE){
        //var_dump($this->geolocation->get_error());
    }
    else{
        //var_dump($city);
        foreach ($city as $c) {
            echo $c->regionName; <-- EROR
        }
        echo "Country code : ".$city['countryName']."\n"; <-- EROR
        echo "Cityname : ".$city['cityName']."\n";  <-- EROR
    }

这是var_dump（$ city）

的值

string(286) "{ "statusCode" : "OK", "statusMessage" : "", "ipAddress" : "202.67.xx.xx", "countryCode" : "ID", "countryName" : "Indonesia", "regionName" : "regionblablabla", "cityName" : "cityblablabla", "zipCode" : "60132", "latitude" : "-7.258", "longitude" : "112.758", "timeZone" : "+07:00" }"

如果使用foreach，则会出错：

Severity: Warning

Message: Invalid argument supplied for foreach()

Filename: controllers/Front.php

Line Number: 105

您能解释如何编写正确的代码来打印每个数据。感谢

Answer 1

您正在获取数组中的响应，请将其替换为：

foreach ($city as $c) { 
    echo $c->regionName;
}

分为：

foreach ($city as $c) { 
    echo "Region :".$c['regionName'];
    echo "Country code : ".$c['countryName']."\n"; 
    echo "Cityname : ".$c['cityName']."\n";
}

Answer 2

您的$city变量包含json响应。解码它。

$city = json_decode($city, true);

你现在有一个循环的数组。

在codeigniter中打印geolocation api中的每个数据

2 个答案: