Question

现有表格t：

namz varchar2(255), sumz number, datez date
-------------------------------------------
John                100.50       01.01.2016
Ivan                200.45       02.02.2014
...
John                400.32       03.03.2016

我是否可以通过使用简单的选择来获得定义期间的月度销售分组：

select namz, .... from t where datez>date1 and datez<=date2 and  ....

得到如下结果：

namz 01.2014  02.2014  03.2014 .... 03.2016
-------------------------------------------
John null     1200.34  234.34 ...   null
Ivan 1234.45  null     null   ...   254.23

提前谢谢！

Answer 1

使用数据集

CREATE TABLE tmp AS 
(SELECT 'John' name, 100.5 Sumz, '01-Jan-16' datez FROM dual UNION
SELECT 'Ivan' name, 200.45 Sumz, '02-Feb-14' datez FROM dual UNION 
SELECT 'John' name, 400.32 Sumz, '03-Mar-16' datez FROM dual UNION
SELECT 'John' name, 200.0 Sumz, '03-Mar-16' datez FROM dual UNION
SELECT 'John' name, 8475.36 Sumz, '01-Jan-18' datez FROM dual UNION
SELECT 'Ivan' name, 8759.36 Sumz, '03-Mar-16' datez FROM dual)
;

使用pivot语句

select * FROM 
(
  SELECT name, sumz, datez
  FROM tmp
)
PIVOT
(
  Sum(sumz)
  FOR datez IN ('01-Jan-16','02-Feb-14','03-Mar-16', '01-Jan-18')
)
ORDER BY name;

它可以为您提供您想要的内容

Answer 2

您可以使用YEAR，MONTH和CONCAT这样的功能：

SELECT namz, CONCAT(MONTH(datez),'.',YEAR(datez)) as d, SUM(something) as s
FROM t
WHERE datez>date1
AND   datez<=date2
GROUP BY namz, d

结果如下：

namez d       s
---------------------
Ivan  01.2014 1234.45
John  02.2014 1200.34
...

Answer 3

SELECT namz,
       SUM( CASE WHEN datez >= DATE '2014-01-01'
                  AND datez  < DATE '2014-02-01'
                 THEN sumz END ) AS "01.2014",
       SUM( CASE WHEN datez >= DATE '2014-02-01'
                  AND datez  < DATE '2014-03-01'
                 THEN sumz END ) AS "02.2014",
       SUM( CASE WHEN datez >= DATE '2014-03-01'
                  AND datez  < DATE '2014-04-01'
                 THEN sumz END ) AS "03.2014"
       -- ...
FROM   t
WHERE  datez >  :date1
AND    datez <= :date2
GROUP BY namz

SQL选择难以分组

3 个答案: