Question

在pandas DataFrame中，我需要过滤掉那些包含单词＆＃39; fixed＆＃39;的列。然后我想创建另一个只包含那些列的DataFrame。我怎么能这样做？

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;
import java.util.List;    

@Entity
    public class User {

        public User() {
        }

        public User(String username, String password) {
            super();
            this.enabled=false;
        }

        @Id
        @GeneratedValue
        private Long id;

        @NotNull
        @Size(min=1, max=45)
        private String username;

        @NotNull
        @Size(min=1, max=60)
        private String password;

        @NotNull
        @Column(name = "enabled")
        private boolean enabled;

        @NotNull
        @Size(min=1, max=45)
        private String email;

        private Integer condo_id;

        @NotNull
        private List<String> roles;
    }

Answer 1

只需使用.ix属性：

fixed = [c for c in dataset.columns if c.startswith("fixed")]
fixed_dataset = dataset.ix[:, fixed]

同样的情况：

non_fixed = [c for c in dataset.columns if not c.startswith("fixed")]
dataset.ix[:, non_fixed]

过滤掉包含特定单词的列

1 个答案: