Question

我有一个包含少量列[ShipAmt]，[Cdate]，....

的表格

我希望按特定月份的每周汇总列并显示它。

本周被认为是从1月底到月底。

如果一周内没有ProductOrders，我想将其总和显示为0.00

示例

Week 1 ---> 2016/03/01 - 2016/03/07

Week 2 ---> 2016/03/08 - 2016/03/14

Week 3 ---> 2016/03/15 - 2016/03/21

Week 4 ---> 2016/03/22 - 2016/03/28

Week 5 ---> 2016/03/29 - 2016/03/31

表格

create table ProductOrders
( 
   [ID] [int] IDENTITY(1,1) NOT NULL,
   [ShipAmt] float not null,
   [Total] float not null,
   [Cdate] datetime not null
)

值

insert into ProductOrders ([ShipAmt], [Total], [Cdate]) 
values (26.99 , 40.00, '2016-03-04 20:26:54.000');
insert into ProductOrders ([ShipAmt], [Total], [Cdate]) 
values (45.00 , 70.88, '2016-03-04 20:28:41.000');
insert into ProductOrders ([ShipAmt], [Total], [Cdate]) 
values (75.00 ,125.00, '2016-03-05 05:39:03.000');
insert into ProductOrders ([ShipAmt], [Total], [Cdate]) 
values (49.00 , 71.99, '2016-02-26 11:21:02.000');

现在我要总结3rd个月的所有列，我尝试了这个。

Select 
Sum([ShipAmt]) [ShipAmt],
Sum([Total]) [Total]
from
(
    SELECT 
    [ShipAmt],
    [Total],
    [Cdate],
    DATEDIFF(week, '2016-03-01', '2016-03-31') AS WeekNumber
    FROM ProductOrders
)
as t1
GROUP BY
WeekNumber

输出

ShipAmt Total
195.99  307.87

所需的输出

ShipAmt Total
146.99  235.88
0.00     0.00
0.00     0.00
0.00     0.00

Answer 1

您的查询应该像

<?php
 session_start();

   include("config.php");

?>
<!DOCTYPE html>
<head>
    <meta charset="utf-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <title>Register Form</title>
    <meta name="description" content="">
    <meta name="viewport" content="width=device-width, initial-scale=1">

    <!-- Place favicon.ico and apple-touch-icon.png in the root directory -->

    <link rel="stylesheet" href="css/main.css">
    <link href='http://fonts.googleapis.com/css?family=Roboto:400,300,500' rel='stylesheet' type='text/css'>
    <link href="//netdna.bootstrapcdn.com/font-awesome/4.1.0/css/font-awesome.min.css" rel="stylesheet">
    <script src="js/jquery-1.8.2.min.js"></script>
    <script src="js/jquery.validate.min.js"></script>
    <script src="js/main.js"></script>
</head>


<body>


  <form method="POST" action="register.php">
  <td>Name</td><td> <input type="text" name="name"></td>
  </tr>
  <tr>
  <td>Email</td><td> <input type="text" name="email"></td>
  </tr>
  <tr>
  <td>Phone </td><td><input type="text" name="phone"></td>
  </tr>
<tr>
  <td>Password</td><td> <input type="password" name="password"></td>
  </tr>
  <tr>
  <td><input id="button" type="submit" name="submit" value="Sign-Up"></td>
  </tr>
  </form>
  </table>
  </fieldset>
  </div>


  <?php

  if("submit"){
    function NewUser()
    {
    $email = $_POST['email'];
    $password = $_POST['password'];
    $name = $_POST['name'];
    $phone =  $_POST['phone'];
    $query = "INSERT INTO php_users_login (email,password,name,phone) VALUES ('$email','$password','$name','$phone')";
    $data = mysql_query ($query)or die(mysql_error());
    if($data)
    {
    echo "YOUR REGISTRATION IS COMPLETED...";
    }
    }

    function SignUp()
    {
    if(!empty($_POST['email']))   //checking the 'user' name which is from Sign-Up.html, is it empty or have some text
    {
    $query = mysql_query("SELECT * FROM php_users_login WHERE `email` = '$_POST[email]' AND `password` = '$_POST[password]'") or die(mysql_error());

    if(!$row = mysql_fetch_array($query) or die(mysql_error()))
    {
    newuser();
    }
    else
    {
    echo "SORRY...YOU ARE ALREADY REGISTERED USER...";
    }
    }
    }
    if(isset($_POST['submit']))
    {
    SignUp();
    }

  }
  else{
    echo "didn't work.";
  }
  ?>

<强>输出：

Answer 2

试试这个

Answer 3

Plz尝试这样的事情

DECLARE @V_DATE DATE = '01-01-2016'
        ,@V_MDATE DATE

SET @V_MDATE = DATEADD(DAY,-1,(DATEADD(MONTH,1,@V_DATE)))

    ;WITH CTE_PRD
AS
(   SELECT  1 AS WNO,@V_DATE AS SDATE,DATEADD(DAY,6,@V_DATE) AS EDATE
    UNION ALL SELECT WNO+1,DATEADD(DAY,1,EDATE),DATEADD(DAY,7,EDATE) FROM CTE_PRD WHERE EDATE <= @V_MDATE
)

SELECT WNO ,ISNULL(SUM([ShipAmt]),0) [ShipAmt],ISNULL(SUM([Total]),0) [Total]
FROM CTE_PRD
INNER JOIN ProductOrders ON  [Cdate] BETWEEN SDATE AND (CASE WHEN EDATE < @V_MDATE THEN EDATE ELSE @V_MDATE END)
GROUP BY WNO

在sql server

3 个答案: