我有以下对象:
var questions = [{
'question_id': 245,
'question': 'Question 1',
'ordinal': 1,
'master_difficulty': 1,
'overridden_difficulty': ''
},{
'question_id': 34,
'question': 'Question 2',
'ordinal': 2,
'master_difficulty': 1,
'overridden_difficulty': ''
},{
'question_id': 656,
'question': 'Question 3',
'ordinal': 3,
'master_difficulty': 1,
'overridden_difficulty': ''
},{
'question_id': 86,
'question': 'Question 4',
'ordinal': 4,
'master_difficulty': 1,
'overridden_difficulty': ''
}]
我希望从中得到最高的序数值。
e.g。 var highestOrdinal = highestOrdinalFunction(questions);
highestOrdinalFunction
将返回最高序数。
所以在这种情况下,它会返回4
。
Math.max
可以为此工作吗?
答案 0 :(得分:4)
Array#reduce
(spec | MDN)是这样做的惯用方法:
function highestOrdinalFunction() {
return questions.reduce(function(previous, entry) {
return previous === undefined || entry.ordinal > previous ? entry.ordinal : previous;
}, undefined);
}
Array#reduce
重复调用一个回调,传入回调的前一个返回值,该值以reduce
的第二个参数播种。那件事通常被称为"累加器"用于减少操作。 reduce
的结果是累加器的最终值。
如果undefined
为空,则上述内容将返回questions
。
答案 1 :(得分:1)
我想这就是你要找的东西:
Math.max.apply(Math,questions.map(function(ques){return ques.ordinal;}))
有关map()如何运作的详情,请参阅Array.prototype.map。
答案 2 :(得分:0)
我们可以通过 ordinal
值对该数组中的对象进行排序,然后返回第一个条目。
function highestOrdinalFunction( questions ) {
return questions.sort( ( a, b ) => a.ordinal - b.ordinal )[ 0 ].ordinal;
}
击> <击> 撞击>
在这个例子中,将Array.prototype.map
和Math.max()
结合起来可能更好一点:
Math.max.apply( null, questions.map(q => q.ordinal) );
答案 3 :(得分:0)
您可以通过两种方式找到最大值。您可以传递函数来映射属性的值,也可以直接在项目上调用属性。对于项目列表,这些结果将是要应用Math.max
计算的映射值。
var questions = [
{'question_id':245,'question':'Question 1','ordinal':1,'master_difficulty':1,'overridden_difficulty':''},
{'question_id':34,'question':'Question 2','ordinal':2,'master_difficulty':1,'overridden_difficulty':''},
{'question_id':656,'question':'Question 3','ordinal':3,'master_difficulty':1,'overridden_difficulty':''},
{'question_id':86,'question':'Question 4','ordinal':4,'master_difficulty':1,'overridden_difficulty':''}
]
document.body.innerHTML = 'Via Function: ' + highestOrdinalValueFn(questions) + '\n';
document.body.innerHTML += 'Via Property: ' + highestOrdinalValueProp(questions);
// #1 : Via function
function highestOrdinalValueFn(items) {
return max(items, function() {
return this.ordinal;
});
}
// #2 : Via property
function highestOrdinalValueProp(items) {
return max(items, 'ordinal');
}
function max(list, prop) {
return Math.max.apply(Math, list.map(function(item) {
return isFunction(prop) ? prop.call(item) : item[prop];
}));
}
function isFunction(fn) {
return fn && {}.toString.call(fn) === '[object Function]';
}
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body { white-space: pre; font-family: monospace; }
&#13;
var questions = [
{'question_id':245,'question':'Question 1','ordinal':1,'master_difficulty':1,'overridden_difficulty':''},
{'question_id':34,'question':'Question 2','ordinal':2,'master_difficulty':1,'overridden_difficulty':''},
{'question_id':656,'question':'Question 3','ordinal':3,'master_difficulty':1,'overridden_difficulty':''},
{'question_id':86,'question':'Question 4','ordinal':4,'master_difficulty':1,'overridden_difficulty':''}
]
document.body.innerHTML = highestValue(questions, 'ordinal');
function highestValue(items, prop) {
return compare(items, function(curr, prev) {
return maxNumericComparator(curr, prev, prop);
})[prop];
}
function maxNumericComparator(curr, prev, prop) {
if (curr && !prev) return -1;
if (!curr && prev) return 1;
if (curr[prop] && !prev[prop]) return -1;
if (!curr[prop] && prev[prop]) return 1;
if (curr[prop] > prev[prop]) return -1;
if (curr[prop] < prev[prop]) return 1;
return 0;
};
function compare(list, comparator) {
return list.reduce(function(max, item) {
return comparator(item, max) < 0 ? item : max;
}, null);
}
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