注意:由于stackoverflow的严格规则,我在http://之后放置一个空格故意打破了我在这里发布的网址。
如果您输入此网址
https:// graph.facebook.com/v2.4/?fields=share{comment_count}&id=http:// kclau.com/investment/where-klci-is-heading /
直接在浏览器中显示:
{" share":{ " comment_count":3}," id":" http:// kclau.com/investment/where-klci-is-heading/" }
精细。所以我准备php如下:
<?php
$url = "http:// kclau.com/investment/where-klci-is-heading/";
$response = file_get_contents("https:// graph.facebook.com/v2.4/?fields=share{comment_count}&id=".$url);
$obj = json_decode($response);
echo $obj->share->comment_count;
?>
它什么都没显示。 我试过var_dump($ obj)display NULL !!
它有什么问题?有人可以帮忙吗?感谢
答案 0 :(得分:0)
我不确定为什么之前的代码无效,但有人向我建议了CURL,它正在运行: -
<?php
$url = "http://kclau.com/investment/where-klci-is-heading/";
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, "https://graph.facebook.com/v2.4/?fields=share{comment_count}&id=".$url);
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->share->comment_count;
?>