这是我的代码
控制器
$query = "SELECT `h`.*,".$countquery.",".$minquery." FROM `abserve_hotels` as `h`";
$aReslts = $this->model->getData($query,$sqlCond);
$this->data['Rooms'] =!empty($aReslts) ? $aReslts : '';
return view('hotel.list', $this->data);
此处,$sqlCond
在传递Ajax和后期操作
查看
<?php
if(($Rooms)){
?>
@foreach($Rooms as $room)
{{ $room->id }}
@endforeach
<?php
}
?>
我尝试了几种设置分页方法的方法。但是它对我起作用了..
我应该如何为此做分页......有人可以帮我!! ..
提前致谢
答案 0 :(得分:1)
您可以使用
手动创建分页器 $pagination = Paginator::make($this->data['Rooms'], count($this->data['Rooms']), 5);
要显示链接,请使用echo $pagination->links();
或{{ $pagination->links() }}
答案 1 :(得分:0)
public function controllerFunction($page=1)
{
$limit = 10;
$start = ($page-1)*$limit;
$query = "SELECT `h`.*,".$countquery.",".$minquery." FROM `abserve_hotels` as `h`";
$aReslts = $this->model->getData($query,$sqlCond)->skip($start)->take($limit);
$this->data['Rooms'] =!empty($aReslts) ? $aReslts : '';
return view('hotel.list', $this->data);
}
这将为您提供分页内容。您可以通过laravel分页或使用自定义代码在视图中添加分页。
答案 2 :(得分:0)
使用这种方式....非常简单
public function items(Request $request)
{
$items = [
'item1',
'item2',
'item3',
'item4',
'item5',
'item6',
'item7',
'item8',
'item9',
'item10'
];
// Get current page form url e.x. &page=1
$currentPage = LengthAwarePaginator::resolveCurrentPage();
// Create a new Laravel collection from the array data
$itemCollection = collect($items);
// Define how many items we want to be visible in each page
$perPage = 1;
// Slice the collection to get the items to display in current page
$currentPageItems = $itemCollection->slice(($currentPage * $perPage) - $perPage, $perPage)->all();
// Create our paginator and pass it to the view
$paginatedItems= new LengthAwarePaginator($currentPageItems , count($itemCollection), $perPage);
// set url path for generated links
$paginatedItems->setPath($request->url());
return view('items_view', ['items' => $paginatedItems]);
}