var storage = chrome.storage.local;
var cachedStorage = {};
这是js文件。虽然我已正确解析,但它显示了意外的令牌。它还显示了其html源页面的意外令牌。任何人都建议我如何对此进行排序。
var defaultStorage = [{
savedPatterns: JSON.stringify([
[{
"en": "English"
}, {
"it": "Italian"
}, "25", true],
[{
"en": "English"
}, {
"la": "Latin"
}, "15", false]
]),
}];
错误发生在这里意外的令牌u
function createPattern() {
console.log('createPattern begin');
var patterns = JSON.parse(S('savedPatterns'));
var srce = [],
trg = [],
prb = [];
console.log(S('savedPatterns'));
console.debug(S('savedPatterns'));
var translator = document.getElementById('translatorService');
var service = translator.children[translator.selectedIndex].value;
srce[0] = document.getElementById('sourceLanguage');
srce[1] = srce[0].children[srce[0].selectedIndex].value;
srce[2] = srce[0].children[srce[0].selectedIndex].text;
trg[0] = document.getElementById('targetLanguage');
trg[1] = trg[0].children[trg[0].selectedIndex].value;
trg[2] = trg[0].children[trg[0].selectedIndex].text;
prb[0] = document.getElementById('translationProbability');
prb[1] = prb[0].children[prb[0].selectedIndex].value;
patterns.push([
[srce[1], srce[2]],
[trg[1], trg[2]],
prb[1],
false,
service
]);
saveBulk({
'savedPatterns': JSON.stringify(patterns)
}, 'Saved Pattern');
console.log('createPattern end');
}
function S(key) {
return cachedStorage[key];
}
function loadStorageAndUpdate(callback) {
storage.get(null, function(data) {
console.log('data: ' + data + ' : ' + JSON.stringify(data));
var d = {};
if (!data || JSON.stringify(data) == '{}') { // in this case, storage was not initialized yet
console.log('setting storage to defaultStorage (stringified): ');
console.log(JSON.stringify(defaultStorage));
storage.set(defaultStorage);
d = defaultStorage;
} else {
d = data;
}
cachedStorage = d;
if (!!callback) {
callback(d);
}
});
}
答案 0 :(得分:1)
当Unexpected token
失败并且取决于字符(在这种情况下为JSON.parse
)时出现错误u
,您可以假设其原因。
try {
JSON.parse(undefined)
} catch (ex) {
document.write(ex.message + "<br/>")
}
try {
JSON.parse({})
} catch (ex) {
document.write(ex.message)
}
您可以尝试这样的事情:
function s(key) {
var obj = {
foo: "foo",
bar: "bar"
}
var v = null;
try {
v = JSON.parse(obj[key]);
} catch () {
v = obj[key];
}
return v;
}
function main() {
var v = s("foo");
}
有关更多信息,请参阅以下帖子。 Uncaught SyntaxError: Unexpected token with JSON.parse
答案 1 :(得分:0)
您正在尝试解析undefined
。当您致电JSON.parse()
时,您正在传递S('savedPatterns')
,而cachedStorage['savedPatterns']
又会尝试访问undefined
,但会以cachedStorage
开头,您无法解析。您可以将var cachedStorage = {
savedPatterns: JSON.stringify([])
};
初始化为:
/*** in your unit test ***/
//... get your grid object ...
const gridComponent = ....
// save the original function to assign it later back
const originalOn = gridComponent.on;
// now mock the on function
gridComponent.on = function(actionName, handler){
assert.ok(true, "on() function has been called");
assert.equal(actionName, "rowclick", "the action on which on() function has been triggered is correct");
}
// execute tested context
this.$('#row0grid_testgrid').trigger('click');
// tidy up
gridComponent.on = originalOn;