Question

我正在编写一个不可能的测验游戏，它确实有效。我希望程序在var fails等于3时退出。

相反，当您输入三次错误答案时，程序会循环而不是退出。

    print("Welcome to impossible quiz")
    print("")
    print("You get 3 fails then you're out")
    print("")
    startcode = int(input("Enter 0 to continue: "))
    fails = 0
    if startcode != 0:
        exit(1)

    print("Welcome")
    print("")
    print("Level one")
    L1ans = input("1+1= ")
    while L1ans != "window":
        print("incorect")
        fails = fails + 1
        L1ans = input("1+1= ")
        if fails = 3:
            exit(1)

Answer 1

if fails == 3:

应该做的工作

Answer 2

欢迎使用Stackoverflow！

我只能看到你的代码有1个问题，所以你几乎就在那里！你的if语句需要有2个相等的符号。

    if fails == 3:
        exit(1)

Answer 3

您的逻辑有点复杂，并且您有语法错误。试试这个：

fails = 0  # Set your failure flag
correct = False  # Set your correct flag
while not correct:  # if not correct loop
    answer = input("1+1= ")  # get the user's answer here
    correct = answer == "window"  # check for correctness
    if not correct:  # Handle incorrect case
        print("Incorrect.")
        fails += 1
        if fails > 3:  # quit if we've looped too much. > is better than == for this
            exit()
print("Correct!")

请注意，这很容易封装在可以处理任何问题的类中：

def ask_question(question, answer, fails) {
    correct = False  # Set your correct flag
    while not correct:  # if not correct loop
        answer = input(question)  # get the user's answer here
        correct = answer == answer  # check for correctness
        if not correct:  # Handle incorrect case
            print("Incorrect.")
            fails += 1
            if fails > 3:  # quit if we've looped too much. > is better than == for this
                exit()
    print("Correct!")
    return fails
}

fails = 0
fails = ask_question("1+1= ", "window", fails)
fails = ask_question("Red and earth is", "Macintosh", fails)

while循环中的Python错误

3 个答案: