Python线程新手 - 它似乎没有什么区别

时间:2016-03-10 19:01:36

标签: python multithreading python-multithreading

我拼凑了一台自动vnc扫描仪。它循环通过IP地址,如果它检测到打开端口5900,它会尝试屏幕截图。它不漂亮,构造不好但是有效。然而它很慢。我尝试过线程,但我一直在努力。你可以看到我已经添加了一个计时器,所以我可以看到扫描30个ip所需的时间。我尝试了多种类型的线程和线程库。这个当前的迭代可能是我用过的最快的迭代,但它比没有线程的速度快几秒。如果你能提供一些反馈,我将不胜感激。

非常感谢

    import socket
    import nmap
    from vncdotool import *
    from ipaddress import *
    import pexpect
    import time
    from multiprocessing import Pool, freeze_support
    from multiprocessing.dummy import Pool as ThreadPool
    import itertools



    def vncconnect(tgtHost):
        try:
            ip = str(tgtHost)
            command = 'vncdotool -v -s ' + ip + ' --delay=1000 capture %s' % (ip + '.jpg')
            child = pexpect.spawn(command)
            child.expect ('INFO:root:connecting')
            time.sleep (10)
            print 'attempting screenshot on ' + ip
            child.expect (pexpect.EOF)
        except:
            pass

    def nmapScan(tgtHost,tgtPort):

        try:
            nmScan = nmap.PortScanner()
            result = nmScan.scan(str(tgtHost),str(tgtPort))
            if (result['nmap']['scanstats']['uphosts'] == '1'):
            print 'Trying ' + tgtHost + ' - appears open: attempting to connect'
            vncconnect(tgtHost)
            f = open('database', 'r+')
                f.write(tgtHost + ' Banner: ' + result['scan']['190.81.24.103']['tcp'][5900]['name'] + result['scan']['190.81.24.103']['tcp'][5900] /               ['version'] + '/n')

            else:
            print 'Trying ' + tgtHost + ' - is not open'
        except:
            pass


    def main():
        net4 = IPv4Address(u'170.0.0.0')
        y = 0
        start = time.time()
        numberofhoststoscan = 30
        while y < numberofhoststoscan:
            try:            

                port = '5900'
                y = y + 1
                z = str(net4)
                nmapScan(z, port)
                net4 = net4 + 1

            except:
                pass            
                net4 = net4 + 1
        end = time.time()
        total = (end - start)   
        print 'total scan time = ' + str(total) + ', scanned ' + str(numberofhoststoscan) + ' hosts'

    if __name__ == "__main__":
        freeze_support()
        pool = ThreadPool(4)
        pool.map(main())
        pool.close() 
        pool.join()

1 个答案:

答案 0 :(得分:3)

看起来像:

  1. 在启动线程池之前执行整个扫描:pool.map(main())。请勿拨打main,只需传递对象:pool.map(main)
  2. 每个线程将开始扫描同一组IP地址。您希望每个线程扫描一组不同的IP地址,以便在它们之间划分工作。
  3. 更新:我会使用generator生成要扫描的地址

    def addressesToScan(firstAddress, numberofhoststoscan):
        net4 = IPv4Address(firstAddress)
        for y in range(numberofhoststoscan):
            yield net4
            net4 = net4 + 1
    

    要使用它,您需要一个接受该地址的函数。要测量总时间,您需要在线程工作者之外进行测量。

    def worker(targetHost):
        port = '5900'
        try:
            nmapScan(targetHost, port)
        except:
            pass
    
    if __name__ == "__main__":
        freeze_support()
        pool = ThreadPool(4)
        start = time.time()
        pool.map(worker, addressesToScan(u'170.0.0.0', 30))
        pool.close()
        pool.join()
    
        end = time.time()
        total = (end - start)   
        print 'total scan time = ' + str(total) + ', scanned ' + str(numberofhoststoscan) + ' hosts'