Question

读取csv文件，遇到隐藏＆＃39;的字符串可以这么说，字符串的长度比打印字符串时出现的长。最终我需要将字符串转换为浮点数。怎么办呢？运行Python 2.7.10 :: Anaconda 2.3.0（x86_64）

代码：

    f=open('Archive_2016-02-23.csv','r')
    for line in f:
        if 'Instrument' in line: #test if header line
            continue #skip header line
    for f,b in zip(l_headers, line.split(',')):
        globals()[f]=b   #makes each header name into a variable with values
    print WPrcAvg, len(WPrcAvg), type(WPrcAvg)
    for i in WPrcAvg:
        print 'i: ', i
    WPrcAvg=WPrcAvg.replace(' ','')
    for i in WPrcAvg:
        print 'i: ', i
    print WPrcAvg, float(WPrcAvg)  #here is where error breaks the code

结果：

2.707 11 <type 'str'>
i:  
i:  2
i:  
i:  .
i:  
i:  7
i:  
i:  0
i:  
i:  7
i:  
i:  
i:  2
i:  
i:  .
i:  
i:  7
i:  
i:  0
i:  
i:  7
i:  
2.707
Traceback (most recent call last):
  File "readtest.py", line 35, in <module>
    print WPrcAvg, float(WPrcAvg)  #here is where error breaks the code
ValueError: could not convert string to float:

Answer 1

一位同事建议使用此代码，它对我有用。不是我理解＆＃34;如何＆＃34;和＆＃34;为什么＆＃34;它，但这有效...

with open('Archive_2016-02-23.csv','rb') as f:
    reader = csv.reader( (line.replace('\0','') for line in f) )
    reader.next()
    for row in reader:
        for f,b in zip(l_headers, row):
            globals()[f]=b   #makes each header name into a variable with values

带有隐藏＆＃39;的字符串字符无法转换为float

1 个答案: