Question

I have the following error in compiler

return  ans;
                ^
  required: byte[]
  found:    int[]

我有这种方法，我想返回一种字节。任何人都可以告诉我如何投射ans以使其与我的方法类型

兼容

public  byte[]  element(int m) {
    //if (q!= a.length)
    // throw new Exception("Array length does not equal k");
    int f;
    int q;
    int[] t;

    this.first = f;
    this.second = q;
    this.data = new int[q];

    for (int i = 0; i < t.length; ++i) {
        this.data[i] = t[i];
    }

    // if (!this.IsValid())
    //  throw new Exception("Bad value from array");


    int ans[] = new int[this.second];

    int a = this.first;
    int b = this.second;
    int x = (choose(this.first,this.second) - 1) - m; // x is the "dual" of m

    for (int i = 0; i < this.second; ++i) {
        ans[i] = largestV(a, b, x); // largest value v, where v < a and vCb < x
        x = x - choose(ans[i], b);
        a = ans[i];
        b = b - 1;
    }

    for (int i = 0; i < this.second; ++i) { 
        ans[i] = (first-1) - ans[i];
        return  ans;
    }
}

注意：我希望它返回字节类型而不是int但我试图转换ans但没有成功。

Answer 1

你必须将int [] ans更改为Byte [] ans，你试图返回一个int数组，但你必须返回你的字节数组

int f;
   int q;
  int [] t;

    this.first = f;
    this.second = q;
    this.data = new int[q];
    for (int i = 0; i < t.length; ++i)
      this.data[i] = t[i];

   // if (!this.IsValid())
    //  throw new Exception("Bad value from array");


        byte ans []= new byte[this.second];

        int a = this.first;
        int b = this.second;
        int x = (choose(this.first,this.second) - 1) - m; // x is the "dual" of m

        for (int i = 0; i < this.second; ++i) {
            ans[i]= largestV(a, b, x); // largest value v, where v < a and vCb < x
            x = x - choose(ans[i], b);
            a = ans[i];
            b = b - 1;
        }

        for (int i = 0; i < this.second; ++i)

            ans[i] = (first-1) - ans[i];

        return  ans;
    }

Answer 2

Dunno为什么你想要int工作并返回byte。除了数据之外，您可以创建一个与ans大小相同的新字节数组，并在最后一个循环中执行此操作

for (int i = 0; i < this.second; ++i)
{ 
    ans[i] = (first-1) - ans[i]);
    ans_byte_version[i] =  (byte) ((first-1) - ans[i]);
}
return ans_byte_version;

然而，如果你告诉我们你想做什么，那会更好。为什么在首先想要字节时声明为int。

如何将int []数据类型转换为byte []数据类型

2 个答案: