我本周开始编码,所以我对它进行了假设。我需要有关在脚本中返回main的帮助。例如,当我完成课程注册部分时,我无法返回菜单程序崩溃
代码:
#include <stdafx.h>
#include <stdio.h>
void eng();
void menu();
void huh();
int main()
{
menu();
return 0;
}
void menu()
{
int menu1choice;
printf("Menu\n");
printf("\n");
printf("1. Student Registration\n");
printf("2. Show Students.\n");
printf("Please enter number: ");
scanf_s("%d", &menu1choice);
switch (menu1choice)
{
case 1:
{
eng();
break;
}
}
}
void eng()
{
int a = 5;
char name[30];
printf("1.Student Number: ");
scanf_s("%d", &a);
//student number
printf("2.Name: ");
scanf_s("%s", &name);
//student name
getchar();
}
void huh()
{
int a = 5;
char name[30];
printf("Your Student number: %d\n", a);
printf("Your Name: %s\n", name);
//result
getchar();
}
请帮我写回程代码行,先谢谢
答案 0 :(得分:0)
这里有一些代码可以帮助你理解函数返回值的机制,在你的情况下回到main函数。
至于一些建议,请阅读魔术数字,特别是它们为什么不好。
/*
* 35917794_main.c
*/
#include <stdio.h>
#define STU_REG 1
#define STU_SHOW 2
#define EXIT_SUCCESS 0
unsigned int show_menu(void);
unsigned int main
(
unsigned int argc,
unsigned char *arg[]
)
{
unsigned int menu1choice;
/*
* The next statements says run the function show_menu() and put the returned
* result in the variable menu1choice.
*/
menu1choice = show_menu();
switch(menu1choice)
{
case (STU_REG):
{
printf("\nGo do STUDENT REGISTRATION things...\n\n");
break;
}
case STU_SHOW:
{
printf("\nGo do SHOW STUDENT things...\n\n");
break;
}
default:
{
printf("\nGo do something for invalid option...\n\n");
break;
}
}
return(EXIT_SUCCESS);
}
unsigned int show_menu
(
void
)
{
unsigned int ui_W0;
printf("Menu\n\n");
printf("1. Student Registration\n");
printf("2. Show Students.\n");
printf("Please enter number: ");
scanf("%d", &ui_W0);
/*
* The next statements says run the function show_menu() has finished and returned
* returns the result in the variable ui_W0.
*/
return(ui_W0);
}