Question

我真的很新的PHP，所以听我说。我创建了一个简单的页面，其中包含一个表单，用于验证您发送的数据是否可以发送，但它在我输入任何内容之前给出了验证错误。下面是代码：

 <html>
 <body>
         <form action="first.php" method="post">
            Username:<input type="text" name="username"><br />
            Password:<input type="password" name="password"><br />
            <input type="submit" name="submit"><br />
         </form>
 <?php
     $errors = array();
     $username = $_POST['username'];
     $password = $_POST['password'];
     $errors = array();
     if(!isset($username) || empty($username)){
        $errors = "Empty username<br />";
      }
     if ($username > 10){
        $errors['username'] = "Username out of range<br />";
     }
     if (!empty($errors)){
         echo "Error<br />";
         print_r ($errors);
     }

 ?>
</body>
</html>

Answer 1

将PHP代码包装到if()条件：

if( isset($_POST['submit']) )
{
    $errors = array();
    (...)
}

如果没有这个，即使没有提交表单，也会执行您的代码。

Answer 2

试试这个：

 <html>
 <body>
        <form action="first.php" method="post">
             Username:<input type="text" name="username"><br />
             Password:<input type="password" name="password"><br />
             <input type="submit" name="submit"><br />
        </form>
        <?php
           if(isset($_POST['submit']))
           {
              $errors = array();
              $username = $_POST['username'];
              $password = $_POST['password'];
              $errors = array();
           if(!isset($username) || empty($username)){
              $errors = "Empty username<br />";
            }
           if ($username > 10){
              $errors['username'] = "Username out of range<br />";
           }
           if (!empty($errors)){
                echo "Error<br />";
                print_r ($errors);
            }
          }
        ?>
</body>
</html>

表格是空的，所以即使在我提交之前它也会给我一个验证错误

2 个答案: