Question

此代码在名为username

的UILabel中显示我的用户caption

caption.text = [NSString stringWithFormat:@"@%@",[data objectForKey:@"username"]];

我希望caption代替他们device token显示该用户username。到目前为止，device token已在应用中成功使用。

//A different Method that successfully handles the device token
 NSMutableDictionary* params =[NSMutableDictionary dictionaryWithObjectsAndKeys:command, @"command",                         [_dataModel deviceToken], @"token", nil ];

＆安培;

//Another different method that successfully handles the device token with a slightly different syntax
NSDictionary *params = @{@"cmd":@"join",
                         //the red text passes user_id to _datamodels userId method and thusly to api.php's handleJoin function 
                         @"token":[_dataModel deviceToken],
                       };

问题：如何编写正确的语法来显示令牌，就像objectforkey值一样？这是我尝试过但我得到编译器警告：no visible interface declaration for selector objectForKey。我知道这可以做到，怎么做？

caption.text = [NSString stringWithFormat:@"@%@",[data objectForKey:@"token":[_dataModel deviceToken]]];

原始j子：数据

//Method body
-(id)initWithIndex:(int)i andData:(NSDictionary*)data
{
self = [super init];
if (self !=nil)
{

Answer 1

试试这个：

select ?boosted where {
    :r1 a ?x
  optional
  {
    ?item rs:boostedBy ?boostedOptional
      bind (if(bound(?boostedOptional), ?boostedOptional, "1"^^xsd:integer) as ?boosted)
  }
}

Answer 2

我认为这将解决您的问题

caption.text = [NSString stringWithFormat:@"%@",[params valueForKey:@"token"]];

NSString stringWithFormat objectForKey自定义Json数据

2 个答案: