Question

如何使用python

在bugzilla中创建新的bug

Bugzilla 5.0.2版和Python 2.7

以下链接说我们可以创建： https://www.bugzilla.org/docs/4.4/en/html/api/Bugzilla/WebService/Bug.html#create

但我正在寻找示例代码

Answer 1

You could also try using python-bugzilla.

https://pypi.python.org/pypi/python-bugzilla/1.2.2

Here is sample code to get a bug.

import bugzilla
bz = bugzilla.Bugzilla(url="https://bugzilla.kernel.org")
print bz.getbug(1)

Answer 2

经过长时间的狩猎，我得到了解决方案...... 想分享

需要安装：easy_install bugsy

这是Python代码：

    import bugsy
    bugsyObj = bugsy.Bugsy(username="user@abc.com", password="passwd23",   userid=None, cookie=None, api_key=None, bugzilla_url='http://11.110.2.212/bugzilla/rest')
    bug = bugsy.Bug()

    bug.product="PRODUCT_REQUEST"
    bug.component="Work for Windows"
    bug.summary = "THIS IS JUST TEST FROM BUGSY"
    bug.add_comment("THE COMMENT SECTION")
    bug.assigned_to="assignuser@abc.com"
    bugsyObj.put(bug)
    bug.id

这将返回Bugzilla的bug id。它需要

Answer 3

用python编写的示例示例，使用其余的API在Bugzilla 5.x中创建一个错误。

import requests

data = {
    "product" : "TestProduct",
    "component" : "TestComponent",
    "summary" : "This is the best bug report",
    "version" : "unspecified",
    "description" : "This is the best GUI for reporting bugs"
}
url_bz_restapi = 'http://localhost/bugzilla/rest.cgi/bug'
r = requests.post(url_bz_restapi, data=data)

Answer 4

import os
while True:
    pass
    os.startfile(your file name)

您的文件名应为文件名，然后是.py
如果我的文件名为hi，应该是

os.startfile(hi.py)

如何使用python在bugzilla中创建新的bug

4 个答案: