Question

我正在尝试在Doctrine2查询生成器中加入表。这是我加入两个表并得到结果的查询。

最初我有两个表要加入：

- ＆GT;雇员 - ＆GT; org_employees

其他表：

- ＆GT;用户

在我的Doctrine2查询构建器代码中，我已经加入了2个表，通过传递组织ID来获取特定组织员工的结果。

SELECT 
* 
FROM org_branch_employees oe
LEFT JOIN employees e ON oe.employee_id  = e.id
WHERE 
oe.org_id = 1;

通过使用查询生成器，上面的sql代码已经改变如下。

$qb = $this->entityManager->createQueryBuilder();
        $qb->select('oe', 'e', 'o')
            ->from('Employee\Entity\OrgEmployee', 'oe')
                ->leftJoin('oe.organization', 'o')
                ->leftJoin('oe.employee', 'e')
                ->where('oe.organization = :organizationId')
                ->setParameter('organizationId', $orgId);
        $query = $qb->getQuery();
        $orgEmployees = $query->getResult();
        return $orgEmployees;

这是我的员工实体：

<?php

namespace Employee\Entity;

use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\ORM\Mapping as ORM;
use Library\Entity\BaseEntity;
use Users\Entity\User;
use Organization\Entity\Organization;

//use Organization\Entity\OrgEmployee;

/**
 * Description of Employee
 *
 * @author Macwin
 */

/**
 * @ORM\Entity
 * @ORM\Table(name="employees")
 */
class Employee extends BaseEntity {

    /**
     * @ORM\OneToOne(
     *     targetEntity="Users\Entity\User"
     * )
     * @ORM\JoinColumn(
     *     name="user_id",
     *     referencedColumnName="id",
     *     nullable=false
     * )
     */
    private $user;

    /**
     * @ORM\Column(name="employee_code", type="string", nullable=true)
     * @var string
     */
    protected $empCode;

    /**
     * @ORM\OneToOne(
     *     targetEntity="Organization\Entity\Organization"
     * )
     * @ORM\JoinColumn(
     *     name="org_id",
     *     referencedColumnName="id",
     *     nullable=false
     * )
     */
    private $organization;

    /**
     * @ORM\OneToMany(targetEntity="Employee\Entity\OrgEmployee", mappedBy="employee")
     */
    protected $orgEmployee;

    /**
     * @ORM\OneToMany(targetEntity="Employee\Entity\OrgEmployeeDesignation", mappedBy="employee")
     */
    protected $orgEmployeeDesignation;

    public function __construct() {
        $this->organizations = new \Doctrine\Common\Collections\ArrayCollection();
        parent::__construct();
    }

    public function getOrganizations() {
        return $this->organizations;
    }

    public function addOrganization(Organization $organization = null) {
        $this->organizations->add($organization);
    }

    public function setUser(User $user = null) {
        $this->user = $user;
    }

    public function getUser() {
        return $this->user;
    }

    public function getEmpCode() {
        return $this->empCode;
    }

    public function setEmpCode($empCode) {
        $this->empCode = $empCode;
    }

    public function setOrganization(Organization $organization = null) {
        $this->organization = $organization;
    }

    public function getOrganization() {
        return $this->organization;
    }

    function getOrgEmployeeDesignation() {
        return $this->orgEmployeeDesignation;
    }

    function setOrgEmployeeDesignation($orgEmployeeDesignation) {
        $this->orgEmployeeDesignation = $orgEmployeeDesignation;
    }

     public function getOrgEmployee() {
        return $this->orgEmployee;
    }

    public function __toString() {
        return __CLASS__ . ": [id: {$this->id}, name: {$this->name}]";
    }
}

这是我的OrgEmployee实体，它映射了Organization表和Enity表，以获取组织详细信息和员工详细信息。

<?php

namespace Employee\Entity;
use Doctrine\ORM\Mapping as ORM;
use Library\Entity\BaseEntity;
use Employee\Entity\Employee;
use Organization\Entity\Organization;

/**
 * Description of Org Employees
 *
 * @author Macwin
 */

/**
 * @ORM\Entity
 * @ORM\Table(name="org_branch_employees")
 */

class OrgEmployee extends BaseEntity{

    /**
     * @ORM\ManyToOne(targetEntity="Employee\Entity\Employee", inversedBy="orgEmployee")
     * @ORM\JoinColumn(name="employee_id",referencedColumnName="id",nullable=false)
     */
    protected $employee;

    /**
     * @ORM\ManyToOne(targetEntity="Organization\Entity\Organization", inversedBy="orgEmployee")
     * @ORM\JoinColumn(name="org_branch_id", referencedColumnName="id", nullable=false)
     */
    protected $organization;

    public function setEmployee(Employee $employee = null)
    {
        $this->employee = $employee;

        return $this;
    }

    public function getEmployee()
    {
        return $this->employee;
    } 

    public function setOrganization(Organization $organization = null)
    {
        $this->organization = $organization;

        return $this;
    }

    public function getOrganization()
    {
        return $this->organization;
    }    


}

以下是我获取组织详细信息和员工详细信息的方式：

'employeeCode' => $orgEmp->getEmployee()->getEmpCode(),


 userFirstName =  $orgEmp->getEmployee()->getUser()->getFirstName(),

正在，员工表有用户表的映射，我可以获取用户信息，

到目前为止一直很好，但是当我想在这里加入更多表时，我无法得出确切的结果。

但是当我需要在上述功能中制作滤镜时，我不确定，怎样才能带来精确的结果。

喜欢按employee_code过滤，用户名。

任何人都可以指导我带来结果。我正在REST API方面将结果提供给客户端。分页也在功能中。

如果我正确地说，我正在尝试以下方法：

SELECT 
* 
FROM org_branch_employees oe
LEFT JOIN employees e ON oe.employee_id  = e.id
LEFT JOIN users u ON e.user_id = u.id 
WHERE 
oe.org_id = 1 AND 
u.user_first_name = "John" and 
e.employee_code = "EMP777"

Answer 1

所以第一个查询是否正常工作？您只需要加入用户实体并添加一些条件？或许我误解了这个问题。

$qb = $this->entityManager->createQueryBuilder();
$qb->select('oe', 'e', 'o', 'user')
  ->from('Employee\Entity\OrgEmployee', 'oe')
  ->leftJoin('oe.organization', 'o')
  ->leftJoin('oe.employee', 'e')
  ->leftJoin('e.user','user')

  ->andWhere('oe.organization = :organizationId')
  ->setParameter('organizationId', $orgId),

  ->andWhere('user.user_first_name = :userFirstName')
  ->setParameter('userFirstName', 'John'),

  ->andWhere('e.employee_code = :employeeCode')
  ->setParameter('employeeCode', 'Emp666');

return $qb->getQuery()->getResult();

在doctrine2中连接表

1 个答案: