如何创建嵌套的php对象

Question

我正在尝试创建一个包含以下图层的php对象。

$obj->property->name;
$obj->property->title;
$obj->property->id;
$obj->property->height;

它给了我＆＃39; Trying to get property of non-object＆＃39;错误

我的对象

$obj = [
   'property' => [
       'name' => 'Rick',
       'title' => 'manager',
       'id' => '123',
       'height' => '5.6'
   ]
];

 $obj = = (object)$obj;

我不确定生成$obj->property->name;的正确语法任何人都可以帮助我吗？我的大脑被解雇了......谢谢！

Answer 1

property object中有一个你不能像那样使用的数组

$obj->property->name;

这应该是：

$obj->property['name'];

示例：

$yourArr = array('property'=>array(
       'name' => 'Rick',
       'title' => 'manager',
       'id' => '123',
       'height' => '5.6'
   ));

$yourObj = (object) $yourArr;
echo $yourObj->property['name']; // Rick

Answer 2

你应该转为object property：

$obj = [
   'property' => [
       'name' => 'Rick',
       'title' => 'manager',
       'id' => '123',
       'height' => '5.6'
   ]
];

$object = (object)$obj;
$object->property = (object)$object->property;

结果：

var_dump($object->property->id); // string(3) "123"
var_dump($object->property->name); // string(4) "Rick"
// etc.