我试图在laravel 5.2中上传带有表单模型绑定的文件。但它不起作用我没有在控制器中获取文件数据。
{!! Form::model($settings, ['route' => ['admin.settings.update', $settings->id], 'class' => 'form-horizontal', 'role' => 'form', 'method' => 'PATCH', 'fiels' => true , 'id' => 'edit-settings']) !!}
<div class="form-group">
{!! Form::file('logo') !!}
</div>
{!! Form::close() !!}
在控制器中我已正确导入输入外墙并尝试获取此类文件对象。
$image = Input::all('logo');
OR
$image = Input::file('logo');
但是我得到了文件的名称而不是文件对象。
答案 0 :(得分:1)
像这样更新你的表单模型,你拼错了文件名
public async Task SetPlayerList()
{
//returns list of players and stores it to be sorted
_Players = await _ItemHandler.GetPlayerList();
_PlayerList = new List<PriceCheckPlayerList>();
//This is as much as I am able to get with my knowledge (I'm lacking)
_Players = _Players.OrderBy()
foreach (Player eap in _Players)
{
_PlayerList.Add(new PriceCheckPlayerList()
{
_Player = eap,
SetYet = false,
LastUpdated = DateTime.UtcNow,
});
}
}
然后在你的控制器中,执行此操作,
{!!Form::model($settings, ['route' => ['admin.settings.update', $settings->id], 'class' => 'form-horizontal', 'role' => 'form', 'method' => 'PATCH', 'files' => true , 'id' => 'edit-settings']) !!}
取而代之的是Input::file('logo');
,因为Input::all('logo');
会返回所有表单输入。所以试试这个Input::all();