Question

这是我为了将英语转换成摩尔斯电码而变得有趣的项目我还是初学者，我自己学习c ++，所以如果问题很愚蠢，我很抱歉，但我没有其他人要求问题是关于第17行任何想法为什么它不称它并重新开始？
代码：

#include <iostream>

using namespace std;
string morse [26] { ".-", "-...", "-.-.", "-..", ".", "..-." , "--." , "....", "..",
                ".---", "-.-", ".-..", "--", "-.", "---", ".--.", "--.-", ".-.", "...",
                "-", "..-", "...-", ".--", "-..-", "-.--", "--.."};
char alphabet [26] {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
void convert();
int main (){
convert();
 cout << "\nExit ?(y/n)\n";
 char ans;
 cin >> ans;
 if (ans=='y') return 0;
 if (ans=='n') convert();} //line 17
 void convert () {
string input ;
int i=0 ;
cout << "Enter your text :\n";
getline(cin,input);
for (i;i < input.length() ;i++) {
        string text = input;
    if (text[i] == alphabet[0]) {cout << morse[0] << " ";}
    if (text[i] == alphabet[1]) {cout << morse[1] << " ";}
    if (text[i] == alphabet[2]) {cout << morse[2] << " ";}
    if (text[i] == alphabet[3]) {cout << morse[3] << " ";}
    if (text[i] == alphabet[4]) {cout << morse[4] << " ";}
    if (text[i] == alphabet[5]) {cout << morse[5] << " ";}
    if (text[i] == alphabet[6]) {cout << morse[6] << " ";}
    if (text[i] == alphabet[7]) {cout << morse[7] << " ";}
    if (text[i] == alphabet[8]) {cout << morse[8] << " ";}
    if (text[i] == alphabet[9]) {cout << morse[9] << " ";}
    if (text[i] == alphabet[10]) {cout << morse[10] << " ";}
    if (text[i] == alphabet[11]) {cout << morse[11] << " ";}
    if (text[i] == alphabet[12]) {cout << morse[12] << " ";}
    if (text[i] == alphabet[13]) {cout << morse[13] << " ";}
    if (text[i] == alphabet[14]) {cout << morse[14] << " ";}
    if (text[i] == alphabet[15]) {cout << morse[15] << " ";}
    if (text[i] == alphabet[16]) {cout << morse[16] << " ";}
    if (text[i] == alphabet[17]) {cout << morse[17] << " ";}
    if (text[i] == alphabet[18]) {cout << morse[18] << " ";}
    if (text[i] == alphabet[19]) {cout << morse[19] << " ";}
    if (text[i] == alphabet[20]) {cout << morse[20] << " ";}
    if (text[i] == alphabet[21]) {cout << morse[21] << " ";}
    if (text[i] == alphabet[22]) {cout << morse[22] << " ";}
    if (text[i] == alphabet[23]) {cout << morse[23] << " ";}
    if (text[i] == alphabet[24]) {cout << morse[24] << " ";}
    if (text[i] == alphabet[25]) {cout << morse[25] << " ";}
    if (text[i] == alphabet[26]) {cout << morse[26] << " ";}
    if (text[i] == ' ') {cout << " / "; }
}

 }

Answer 1

您的代码中存在一些问题，但是关于程序没有循环的原因，那是因为您没有告诉它循环，您只能告诉它调用转换（）第二次。

int main (){
    convert();  // first call
    cout << "\nExit ?(y/n)\n";
    char ans;
    cin >> ans;
    if (ans=='y') return 0;
    if (ans=='n') convert(); //line 17
    // program ends
}

这里有一个次要问题，你只读了ans的一个字符，这意味着你没有读过＆＃34; \ n＆＃34;行尾，因此getline()内的convert会认为有一个空行。

您可能想尝试：

int main()
{
    bool quitting = false;

    while (!quitting)
    {
        convert();
        std::cout << "\nExit? (y/N): " << std::flush;
        std::string ans = "";
        std::getline(std::cin, ans);
        if (!ans.empty() && (ans[0] == 'y' || ans[0] == 'Y'))
            quitting = true;
    }
}

无法调用函数C ++

1 个答案: