Question

我想使用PHP处理来自mysql的数据，以便在HTML中显示。我有三个数据库表：学生，课程，student_x_course

学生：

| idStudent | firstname | surname |
-----------------------------------
| 1         | John      | Regular | 
| 2         | John      | Smith   | 
| 3         | Claire    | White   |

当然：

| idCourse  | coursename |
--------------------------
| 1         | Art        | 
| 2         | Music      |
| 3         | Math       |
| 3         | Biology    |

student_x_course：

| idsc | idStudent | idCourse |
-------------------------------
| 1    | 1         | 1        |
| 2    | 1         | 2        |
| 3    | 1         | 3        |
| 4    | 2         | 1        |
| 5    | 2         | 2        |
| 6    | 2         | 4        |
| 7    | 3         | 1        |
| 8    | 3         | 2        |
| 9    | 3         | 3        |
| 10   | 3         | 4        |

我想创建一个看起来像这样的html表：

              | Art  | Music | Math  | Biology |
------------------------------------------------
John Regular  | x    | x     | x     | -       |
John Smith    | x    | x     | -     | x       |
Claire White  | x    | x     | x     | x       |

我的SQL查询是： SELECT s.firstname，s.surname，c.coursename FROM student AS s INNER JOIN student_x_course AS sxc ON（s.idStudent = sxc.idStudent）INNER JOIN课程ON（c.idCourse = sxc.idCourse）;

让我得到以下信息：

 | John   | Regular | Art     |
 | John   | Regular | Music   |
 | John   | Regular | Math    |
 | John   | Smith   | Art     |
 | John   | Regular | Music   |
 | John   | Smith   | Biology |
 | Claire | White   | Art     |
 | Claire | White   | Music   |
 | Claire | White   | Math    |
 | Claire | White   | Biology |

我的问题是：如何从多行到多行？是否有更好的SQL查询或我必须在PHP代码中处理这个？有什么建议吗？

Answer 1

您正试图转动结果。在mysql中，您可以使用conditional aggregation执行此操作：

SELECT s.idStudent, s.firstname, s.surname, 
   max(case when c.coursename = 'Art' then 'x' end) Art,
   max(case when c.coursename = 'Music' then 'x' end) Music,
   max(case when c.coursename = 'Math' then 'x' end) Math,
   max(case when c.coursename = 'Biologoy' then 'x' end) Biologoy
FROM student AS s 
   INNER JOIN student_x_course AS sxc ON (s.idStudent = sxc.idStudent) 
   INNER JOIN course ON (c.idCourse = sxc.idCourse)
GROUP BY s.idStudent

处理来自mysql的数据以获取html

1 个答案: