Question

我想知道有没有办法在数据库等待/休眠状态下从表中回显第一行5秒然后回显第二行？

提前感谢您的帮助！

$conn = mysqli_connect('localhost', 'root', '','database');
$strSql=$conn->query("SELECT words FROM load ORDER BY id ASC ");
if($strSql->num_rows >0) {
    while ($row = $strSql->fetch_assoc()) {
    $rows[]=$row;
    foreach($rows as $row){
       $words1=$row['words'];
               echo '<div class="animatedText"> '.$words1.'</div>';
       //let's say sleep(5); and then print second row???
       }
   }
}

Answer 1

尝试使用output buffering。例如：

header( 'Content-type: text/html; charset=utf-8' );

while ($row = $strSql->fetch_assoc()) {
      $rows[]=$row;
       foreach($rows as $row){
            $words1=$row['words'];
            echo '<div class="animatedText"> ';
            echo $words1;
            echo '</div>';
            flush();
            ob_flush();
            sleep(5);
           }
       }

Answer 2

您可以使用sleep()功能：

echo '<div class="animatedText"> ';
while ($row = $strSql->fetch_assoc()) {

      $rows[]=$row;

       foreach($rows as $row){
           $words1=$row['words'];

           echo $words1;
           sleep(5);

           }

       }
echo '</div>';

php echo第一行等待/睡眠然后回显第二行

2 个答案: