Question

我想创建一个矩阵数组来分割图像。

以下是我为创建数组所做的工作，它显示了＆＃34; EXC_I386_GPFLT＆＃34;的错误。

我该如何解决它或我该怎样做才能实现我的目的？

#include "opencv2/core/core.hpp"
#include "opencv2/highgui/highgui.hpp"
#include "opencv2/imgproc/imgproc.hpp"
#include "iostream"

using namespace cv;
using namespace std;

int main( )
{

    Mat img;
    img = imread("/Users/koike1979/Documents/0306/trucka.bmp", CV_LOAD_IMAGE_COLOR);
    namedWindow( "Original image", CV_WINDOW_AUTOSIZE );
    imshow( "Original image", img );

    Mat H[2]= {Mat(20,20,CV_8UC1),Mat(20,20,CV_8UC1)};

    for (int i=0; i<200; i++)
        for (int j=0; j<200; j++)
    {

    Vec3b intensity2 = img.at<Vec3b>(i ,j);
    int blue = intensity2.val[0];
    int green = intensity2.val[1];
    int red = intensity2.val[2];
        H[0].at<uchar>(i,j)=(blue+green+red)/3;
            }
    namedWindow( "Modify pixel", CV_WINDOW_AUTOSIZE );
    imshow( "Modify pixel", H[0] );
    waitKey(0);

    return 0;
}

Answer 1

https://stackoverflow.com/a/19652248/4518710

创建矩阵数组的主要目的是什么？您的代码似乎有一些问题，

首先，您需要通过硬编码访问Mat NOT的坐标请改用Mat :: rows和Mat :: cols 原：

for (int i=0; i<200; i++)
    for (int j=0; j<200; j++)
    {
    }

改性：

int rows = img.rows;
if(rows > 200)
    rows = 200;
int cols = img.cols;
if(cols > 200)
    cols = 200;

for (int i=0; i<rows; i++)
    for (int j=0; j<cols; j++)
    {
    }

其次，使用向量＆lt;＆gt; C ++的特性而不是数组本身原：

Mat H[2]= {Mat(20,20,CV_8UC1),Mat(20,20,CV_8UC1)};

改性：

std::vector<Mat> H;
H.push_back(Mat(20, 20, CV_8UC1));
H.push_back(Mat(20, 20, CV_8UC1));

第三，直接将int转换为uchar可能会产生潜在的副作用请改用static_cast 原：

H[0].at<uchar>(i,j)=(blue+green+red)/3;

改性：

H[0].at<uchar>(i,j) = static_cast<uchar>((blue+green+red)/3);

Answer 2

您可以使用std :: vector

Mat img;
img = imread("./res/mydhm.png", CV_LOAD_IMAGE_COLOR);
namedWindow("Original image", CV_WINDOW_AUTOSIZE);
imshow("Original image", img);

//Mat H[2] = { Mat(img.cols, img.row, img.type), Mat(img.cols, img.row, img.type) };
std::vector<Mat> H; // use vector
H.push_back(Mat(img.cols, img.rows, img.type()));
H.push_back(Mat(img.cols, img.rows, img.type()));

for (int i = 0; i<img.cols; i++)
{
    for (int j = 0; j<img.rows; j++)
    {
        Vec3b intensity2 = img.at<Vec3b>(Point(i, j));
        int blue = intensity2.val[0];
        int green = intensity2.val[1];
        int red = intensity2.val[2];
        H[0].at<Vec3b>(Point(i, j)) = (uchar)(blue + green + red) / 3;
    }
}
namedWindow("Modify pixel", CV_WINDOW_AUTOSIZE);
imshow("Modify pixel", H[0]);
waitKey(0);

不要忘记#include<vector>

我应该如何使用openCV创建一个矩阵数组

2 个答案: