Question

使用休眠..我现在正在学习这项技术..不知道我错在哪里......请指导一下..

我在尝试将类型的数据库 - TIMESTAMP（）映射到Pojo变量时看到上述错误... 我尝试将变量类型更改为日期...日历...时间戳..这里没有任何作用... 问题似乎与列的映射有关...对此的任何帮助都非常感谢......

我的pojo课程：

public class Pojo_****
{ ......... 
private Date C_TimeStamp; 
private Date L_TimeStamp;
}

我的数据库表：

Table_****
    ..........
    C_TimeStamp TIMESTAMP(6)
    L_TimeStamp TIMESTAMP(6)

我的配置xml：

 Pojo_****.hbm.xml
        ......
        <property name="C_TimeStamp" column="C_TimeStamp" />
        <property name="L_TimeStamp" column="L_TimeStamp" />

错误日志：

In Main method of MainApp...
Mar 9, 2016 2:48:14 PM org.hibernate.cfg.Environment <clinit>
INFO: Hibernate 3.2 cr4
Mar 9, 2016 2:48:14 PM org.hibernate.cfg.Environment <clinit>
INFO: hibernate.properties not found
Mar 9, 2016 2:48:14 PM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: Bytecode provider name : cglib
Mar 9, 2016 2:48:14 PM org.hibernate.cfg.Environment <clinit>
INFO: using JDK 1.4 java.sql.Timestamp handling
Mar 9, 2016 2:48:15 PM org.hibernate.cfg.Configuration configure
INFO: configuring from resource: hibernate.cfg.xml
Mar 9, 2016 2:48:15 PM org.hibernate.cfg.Configuration getConfigurationInputStream
INFO: Configuration resource: hibernate.cfg.xml
Mar 9, 2016 2:48:15 PM org.hibernate.cfg.Configuration addResource
INFO: Reading mappings from resource: Pojo_****.hbm.xml
Mar 9, 2016 2:48:15 PM org.hibernate.cfg.HbmBinder bindRootPersistentClassCommonValues
INFO: Mapping class: Pojo_****-> Table_****
Mar 9, 2016 2:48:15 PM org.hibernate.cfg.Configuration doConfigure
INFO: Configured SessionFactory: null
Failed to create sessionFactory object.org.hibernate.MappingException: Could not determine type for: Timestamp, for columns: [org.hibernate.mapping.Column(L_TimeStamp)]
Exception in thread "main" java.lang.ExceptionInInitializerError
    at tutorialspoint.example.MainApp.main(MainApp.java:29)
Caused by: org.hibernate.MappingException: Could not determine type for: Timestamp, for columns: [org.hibernate.mapping.Column(L_TimeStamp)]
    at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:266)
    at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:253)
    at org.hibernate.mapping.Property.isValid(Property.java:185)
    at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:410)
    at org.hibernate.mapping.RootClass.validate(RootClass.java:192)
    at org.hibernate.cfg.Configuration.validate(Configuration.java:1026)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1211)
    at tutorialspoint.example.MainApp.main(MainApp.java:21)

Answer 1

尝试将DateTime填充到变量中。我在项目中遇到了同样的问题。

  Pojo_Class obj_Pojo = new Pojo();

try {
            //Or Pass any Date Object.
        obj_Pojo.setC_TimeStamp(new SimpleDateFormat("yyyy/MM/dd HH:mm:ss").parse(String.valueOf(new Date().getTime()))); 

    } catch (ParseException e) {
        v_objBorrower.setCreationDate(new Date());
    }

注意： - 将数据库列更改为DateTime。这可能会帮助你。如果没有任何配置问题。

Answer 2

您是否尝试添加类型=＆＃34;时间戳＆＃34;在你的.hbm.xml文件中，像这样？

<property name="C_TimeStamp" column="C_TimeStamp" type="timestamp" />
<property name="L_TimeStamp" column="L_TimeStamp" type="timestamp" />

据我所知，时间不被认为是xml配置中的基本类型，因此应该是映射文件的一部分。

引起：org.hibernate.MappingException：无法确定类型：Timestamp，对于列：[org.hibernate.mapping.Column（***）]

2 个答案: