Question

我必须展示＆＃34;生日＆＃34;日期格式＆＃39; dd.mm＆＃39;来自格式＆＃39; dd.mm.yy＆＃39;但只有那个＆＃34;生日＆＃34;有超过10名员工，名为＆＃34; employeeFirm＆＃34;。

当我离开时：select birthday from employeeFirm; 我明白了：

01.11.73
08.09.77
01.11.65
01.11.74
(null)
(null)
01.11.85
(null)
01.11.88
01.11.65
01.11.56
01.11.77
01.11.77
(null)
01.11.77
01.11.77 
....

我想以格式＆＃39; dd.mm＆＃39;来获取记录，在这种情况下是＆＃34; 01.11＆＃34;因为我们在同一天生日时有超过10名员工。

Answer 1

您可以像这样使用TO_CHAR：

SELECT case when t.formated is not null
            then t.formated
            else to_char(s.birthday,'DD.MM.YYYY')
       end as new_birthDay
FROM employeeFirm s
LEFT OUTER JOIN(SELECT TO_CHAR(birthday,'DD.MM') as formated
                FROM employeeFirm
                GROUP BY TO_CHAR(birthday,'DD.MM') 
                HAVING COUNT(*) > 10) t
ON(to_char(s.birthday,'DD.MM') = t.formated)

如果您只想在当天拥有超过10名员工的生日，那么：

SELECT TO_CHAR(birthday,'DD.MM') as formated
FROM employeeFirm
GROUP BY TO_CHAR(birthday,'DD.MM') 
HAVING COUNT(*) > 10

Answer 2

试试这个：

SELECT ddmm, count
FROM (
    SELECT distinct Substr(Birthday,1,5) as ddmm
        , Count(Birthday) OVER(PARTITION BY  Substr(Birthday,1,5)) AS count
    from employeeFirm
) A
where count> 10

Answer 3

WITH t AS 
(SELECT dob,count(*) OVER (PARTITION BY dob ORDER BY dob) counting FROM employeeFirm)
SELECT dob,
CASE WHEN counting >10 
THEN to_char(dob,'DD-MM') ELSE to_char(dob,'DD-MM-YYYY') 
end  
FROM t;

显示＆＃34;生日＆＃34;日期格式＆＃39; dd.mm＆＃39;来自格式＆＃39; dd.mm.yy＆＃39;但只有那个＆＃34;生日＆＃34;拥有10多名员工

3 个答案: