Question

我正在尝试使用angulards

中的formdata对象创建上传文件

<?php
   $sql=mysql_query("SELECT * FROM category")or die(mysql_error());
   $result=mysql_fetch_array($sql);
   for($i=0;$i<$result;$i++)
   {  
     $cat_id=mysql_result($get_cat,$i,'category_id');
     $cat=mysql_result($get_cat,$i,'category_name');
     $category_icon=mysql_result($get_cat,$i,'category_icon');
     echo $cat_id;
     echo $cat . '<img src="data:image/jpeg;base64,' . base64_encode($num_cat['category_icon']) . '" width="290" height="290">' ;
   }
?>

希望在mvc 6中使用webapi2编写c＃控制器代码代码

Answer 1

var fd = new FormData();
    fd.append('file', $scope.teamLogo);
    fd.append('aa', 'a');
    $http.post('http://localhost:51815/api/upload/', fd, {
        transformRequest: saangular.identity,
        headers: { 'Content-Type': undefined }
    }).then(function (teamList) { });

控制器中的

public async Task<HttpResponseMessage> PostFormData()
    {
        // Check if the request contains multipart/form-data.
        if (!Request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
        }

        string root = HttpContext.Current.Server.MapPath("~/App_Data");
        var provider = new MultipartFormDataStreamProvider(root);

        try
        {
            // Read the form data.
            await Request.Content.ReadAsMultipartAsync(provider);

            // This illustrates how to get the file names.
            foreach (MultipartFileData file in provider.FileData)
            {
               // Trace.WriteLine(file.Headers.ContentDisposition.FileName);
                //Trace.WriteLine("Server file path: " + file.LocalFileName);
            }
            return Request.CreateResponse(HttpStatusCode.OK);
        }
        catch (System.Exception e)
        {
            return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e);
        }
    }

在js文件中使用此代码

如何使用angularjs（formData）在MVC 6 web api2中上传文件

1 个答案: